• the vertical axis represents the speed of a motion 

• the horizontal axis represents the time taken 

• the gradient of graph represents the rate of change of speed with respect to time, that is acceleration 

\(P\)

• The speed of object increases from \(0 \space ms^-1\) to  \(16 \space ms^-1\)
• The gradient of graph is positive, hence the rate of change of speed is positive 
• \(\text{Acceleration} = \dfrac{\text{Change of speed}}{\text{Changein time}}\)
• The area of triangle \(OAP\) that is the area represents the distance travelled in the period of \(10s\)

\(Q\)

• There is no change of speed (zero gradient)
• The object moves at a uniform speed
• The area of square under \(Q\) represents the distance travelled in the period of \((20-10)s\)

\(R\)

• Speed of the object decreases 
• The gradient of graph is negative, hence the rate of change of speed is negative 
• \(\text{Deceleration} = \dfrac{\text{Change of speed}}{\text{Change in time}}\)
• There is no change in direction in which the motion of the object remains in the same direction 
•  The area of triangle \(BCR\) that is the area represents the distance travelled in the period of \((25-20)s\)

• the vertical axis represents the speed of a motion 

• the horizontal axis represents the time taken 

• the gradient of graph represents the rate of change of speed with respect to time, that is acceleration 

\(P\)

• The speed of object increases from \(0 \space ms^-1\) to  \(16 \space ms^-1\)
• The gradient of graph is positive, hence the rate of change of speed is positive 
• \(\text{Acceleration} = \dfrac{\text{Change of speed}}{\text{Changein time}}\)
• The area of triangle \(OAP\) that is the area represents the distance travelled in the period of \(10s\)

\(Q\)

• There is no change of speed (zero gradient)
• The object moves at a uniform speed
• The area of square under \(Q\) represents the distance travelled in the period of \((20-10)s\)

\(R\)

• Speed of the object decreases 
• The gradient of graph is negative, hence the rate of change of speed is negative 
• \(\text{Deceleration} = \dfrac{\text{Change of speed}}{\text{Change in time}}\)
• There is no change in direction in which the motion of the object remains in the same direction 
•  The area of triangle \(BCR\) that is the area represents the distance travelled in the period of \((25-20)s\)