Given \(\dfrac{d}{dx}(4x^2)=8x\), find \(\int 8x \, dx\).
Differentiation of \(4x^2\) is \(8x\).
By the reverse of differentiation, the integration of \(8x\) is \(4x^2\).
Hence, \(\int 8x \, dx=4x^2\).
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