How much should be subtracted from \(3\,206\text{ g}\) so that it becomes \(1.507\text{ kg}\) ?
SOLUTION:
Convert \(3\,206\text{ g}\) to \(\text{kg}\).
\(3\,206\text{ g}\div1000=3.206\text{ kg}\)
Mathematical Equation.:
\(3.206\text{ kg}-\Box\text{ kg}=1.507\text{ kg}\)
To find \(\Box\), we will rearrange the equation to
\(3.206\text{ kg}-1.507\text{ kg}=\Box\text{ kg}\)
\(\begin{array}{lr} &\overset{2}{\cancel3}.\overset{11}{\cancel2}\overset{9}{\cancel0}\overset{16}{\cancel6}\text{ kg}\\ -&1.5\,07\,\text{ kg}\\ \hline&1.6\,99\,\text{ kg} \\\hline\end{array}\)
Therefore, \(1.600\text{ kg}\)needs to be subtracted from \(3\,206\text{ g}\) to become \(1.507\text{ kg}\).
|