Rusting

 

Conditions for rusting of an iron

  • Oxygen gas
  • Water
 

Redox reaction of rusting

 
Step Explanation
Oxidation
  • Iron atom releases two electrons to form iron(II) ion, \(Fe^{2+}\)
    • \(Fe(s)\rightarrow Fe^{2+}(aq)+2e^-\\\)
  • The released electrons would flow through the iron to the surface. 
  • Iron is an electrical conductor, thus the electrons are able to flow through the iron. 
  • There is oxygen gas at the surface. 
Reduction
  • The released electrons from the oxidation process are received by oxygen gas. 
  • Since oxygen gas received electrons, oxygen is reduced to form hydroxide ion, \(OH^-\)
    •  \(O_2(g)+2H_2O(l) +4e^-\rightarrow 4OH^-(aq)\)
Formation of a chemical cell
  • The part of the system that undergoes oxidation is the negative terminal of the chemical cell. 
  • The part of the system that undergoes reduction is the positive terminal of the chemical cell. 
    • \(2\times [Fe(s)\rightarrow Fe^{2+}(aq)+2e^-]\\ O_2(g)+2H_2O(l) +4e^-\rightarrow 4OH^-(aq)\\ \text{Equals to}\\2Fe(s)+O_2(g)+2H_2O(l)\rightarrow 2Fe^{2+}(aq)+4OH^-(aq) \)
Formation of rust
  • The iron(II) ions, \(Fe^{2+}\) flow from the negative terminal to the positive terminal. 
  • At the positive terminal, the iron(II) ions, \(Fe^{2+}\) reacts with the hydroxide ion, \(OH^-\) to form iron(II) hydroxide, \(Fe(OH)_2\)
    • \(Fe(aq)+2OH^-(aq)\rightarrow Fe(OH)_2(s)\\\)
  • The iron(II) hydroxide is oxidised to form iron(III) hydroxide, \(Fe(OH)_3\)
    • \(4Fe(OH)_2(s)+O_2(g)+2H_2O(l)\rightarrow 4Fe(OH)_3(s)\\\)
  • The iron(III) hydroxide, \(Fe(OH)_3\). then forms rust. 
  • Rust is hydrated iron(III) hydroxide, \(Fe_2O_3.3H_2O\)
    • \( 4Fe(OH)_3(s)\rightarrow Fe_2O_3.3H_2O(s)\\ \phantom{ 4Fe(OH)_3(s)\rightarrow}Rust\)

 

Formation of rust
 

Metal corrosion

  • Definition: oxidation of metal through the action of air or oxygen gas, water and/or electrolyte.
  • The oxidised metal would release electron(s) to form an ion.
 

Prevention of metal corrosion using a more electropositive metal

  • Metal corrosion can be prevented by touching a more electropositive metal with the metal being protected.
  • The more electropositive metal releases electrons easier.
  • For example; a layer of zinc protecting an iron, but there is a scratch on the layer of zinc.
    • Zinc is more electropositive than iron.
    • Zinc is oxidised by releasing electrons.
    • Electrons flow to the surface of iron where there are water and oxygen.
  • Instead of iron being oxidised, the zinc layer acts as a sacrificial layer of protection. 
 
Zinc layer as a sacrificial layer of protection
 

Prevention of metal corrosion using a less electropositive metal

  • A layer of less electropositive metal (e.g. tin) protecting iron can still prevent corrosion of iron.
  • However, if the protective layer is scratched, the corrosion of iron is enhanced instead of prevented.
  • The more electropositive metal releases electrons easier.
  • For example; a layer of tin protecting an iron, but there is a scratch on the layer of tin.
    • Iron is more electropositive than tin.
    • Iron is oxidised by releasing electrons.
    • Electrons flow to the surface of iron where there are water and oxygen.
  • Instead of tin being oxidised, the iron is oxidised at a faster rate because iron is more electropositive than tin.