Find the duration, in centuries and years, between \(6\frac{7}{10}\) centuries and 9.8 centuries.
Solution
To find the duration, the smaller term will be substracted from the bigger terms.
\(9.8\text{ centuries} - 6\frac{7}{10}\text{ centuries}=\Box\text{ centuries }\Box\text{ years}\)
We need to standardize the unit of all terms.
\(6\frac{7}{10}\text{ centuries}\to6.7\text{ centuries}\)
Solve.
\(9.8\text{ centuries} - 6.7\text{ centuries}=\Box\text{ centuries }\Box\text{ years}\)
\(\begin{array}{lr} &9.8\text{ centuries}\\ -&6.7\text{ centuries}\\ \hline&3.1\text{ centuries} \end{array}\)
Convert 3.1 centuries to centuries and years.
\(3.1\text{ centuries}\to3\text{ centuries}(0.1\times1000)\text{ years}\)
\(3.1\text{ centuries}\to3\text{ centuries}100\text{ years}\)
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