Basic Identities

6.4 Basic Identities - Additional Mathematics Form 5
ADDITIONAL MATHEMATICS • Form 5 • Chapter 6: Trigonometric Functions

6.4 Basic Identities

A trigonometric identity is an equation that involves trigonometric functions and holds true for all valid values of the angle. In this topic, we derive three fundamental Pythagoras identities using right-angled triangles and unit circles: \(\sin^2 \theta + \cos^2 \theta = 1\), \(1 + \tan^2 \theta = \sec^2 \theta\), and \(1 + \cot^2 \theta = \text{cosec}^2 \theta\). We then apply these identities to evaluate trigonometric expressions without using a calculator and to verify and prove various trigonometric identities.

Learning Objectives

  • Derive the three basic trigonometric identities (Pythagoras identities) using a right-angled triangle and Pythagoras' theorem.
  • Use basic trigonometric identities to determine values of expressions without using a calculator.
  • Prove trigonometric identities systematically by simplifying expressions on one or both sides using basic identities, quotient identities, reciprocal identities, or conjugates.

The Hexagon and Division Triangle of Pythagoras Identities

Visualise how the three basic identities connect directly to Pythagoras' theorem \(a^2 + b^2 = c^2\).

From Pythagoras' Theorem to the Three Basic Identities

1

Start with \(a^2 + b^2 = c^2\).

2

Divide by \(c^2\): \(\sin^2 A + \cos^2 A = 1\).

3

Divide by \(b^2\): \(1 + \tan^2 A = \sec^2 A\).

4

Divide by \(a^2\): \(1 + \cot^2 A = \text{cosec}^2 A\).

Identity 1

\(\sin^2 \theta + \cos^2 \theta = 1\)

Divide \(a^2 + b^2 = c^2\) by \(c^2\).

Identity 2

\(1 + \tan^2 \theta = \sec^2 \theta\)

Divide \(a^2 + b^2 = c^2\) by \(b^2\).

Identity 3

\(1 + \cot^2 \theta = \text{cosec}^2 \theta\)

Divide \(a^2 + b^2 = c^2\) by \(a^2\).

Unit Circle Form

\(x^2 + y^2 = 1\)

Where \(x = \cos \theta\) and \(y = \sin \theta\).

Short Explanation

All basic trigonometric identities stem directly from Pythagoras' theorem.

1. Definition and Fundamental Reciprocal & Quotient Identities

A trigonometric identity is an equation involving trigonometric functions that is valid for any values of the angle. Reciprocal and quotient identities: \(\tan \theta = \dfrac{\sin \theta}{\cos \theta}\), \(\cot \theta = \dfrac{1}{\tan \theta} = \dfrac{\cos \theta}{\sin \theta}\), \(\text{cosec } \theta = \dfrac{1}{\sin \theta}\), \(\sec \theta = \dfrac{1}{\cos \theta}\).

2. Derivation of the Three Basic Identities

From a right-angled triangle \(ABC\) with sides \(a\), \(b\), and hypotenuse \(c\) where angle \(A\) is considered: \(\sin A = \dfrac{a}{c}\), \(\cos A = \dfrac{b}{c}\), \(\tan A = \dfrac{a}{b}\), \(\text{cosec } A = \dfrac{c}{a}\), \(\sec A = \dfrac{c}{b}\), \(\cot A = \dfrac{b}{a}\). By Pythagoras' theorem: \(a^2 + b^2 = c^2\).

3. Evaluating Expressions Without a Calculator

Using rearrangement of basic identities: \(\sin^2 (-430^\circ) + \cos^2 (-430^\circ) = 1\) since \(\sin^2 \theta + \cos^2 \theta = 1\) for any angle \(\theta\). Also, \(\tan^2 \left(\dfrac{\pi}{3}\right) - \sec^2 \left(\dfrac{\pi}{3}\right) = -1\) since \(1 + \tan^2 \theta = \sec^2 \theta \implies \tan^2 \theta - \sec^2 \theta = -1\).

4. Proving Trigonometric Identities

Proofs can be done by simplifying the expression on the left-hand side (LHS) until it matches the right-hand side (RHS), simplifying the RHS until it matches the LHS, or simplifying both LHS and RHS independently until both arrive at the exact same simplified expression.

IdentityDerived by dividing \(a^2 + b^2 = c^2\) byRearranged form
\(\sin^2 \theta + \cos^2 \theta = 1\)\(c^2\)\(\sin^2 \theta = 1 - \cos^2 \theta\)
\(1 + \tan^2 \theta = \sec^2 \theta\)\(b^2\)\(\sec^2 \theta - \tan^2 \theta = 1\)
\(1 + \cot^2 \theta = \text{cosec}^2 \theta\)\(a^2\)\(\text{cosec}^2 \theta - \cot^2 \theta = 1\)

Excellent Tips for Proving Identities

1

Prove from the more complex side.

2

Convert expressions to basic trigonometric ratios form (in terms of \(\sin\) and \(\cos\)).

3

Multiply by a conjugate if required, e.g. when terms like \(1 + \cos \theta\) or \(1 - \sin \theta\) appear in denominators.

4

Combine fractions over a common denominator and substitute basic identities directly.

Example 18(a): Prove \(1 - 2\sin^2 A = 2\cos^2 A - 1\)

\(\text{LHS} = 1 - 2(1 - \cos^2 A) = 2\cos^2 A - 1 = \text{RHS}\)

Substitute \(\sin^2 A = 1 - \cos^2 A\).

Example 18(b): Prove \(\tan A + \cot A = \sec A \text{ cosec } A\)

\(\text{LHS} = \dfrac{\sin A}{\cos A} + \dfrac{\cos A}{\sin A} = \dfrac{1}{\cos A \sin A} = \text{RHS}\)

Combine fractions using \(\sin^2 A + \cos^2 A = 1\).

Try to Answer First

Answer in your mind, then press "Check Answer".

1

Without using a calculator, find the value of \(\sec^2 173^\circ - \tan^2 173^\circ\).

2

Given \(\cos \theta = m\), express \(\tan^2 \theta\) in terms of \(m\).

3

Prove the identity: \(\dfrac{\sin^2 \theta}{1 + \cos \theta} = 1 - \cos \theta\).

Common Mistakes

  • !Sign errors when rearranging: Writing \(\tan^2 \theta - \sec^2 \theta = 1\) instead of \(-1\), or \(\cot^2 \theta - \text{cosec}^2 \theta = 1\) instead of \(-1\).
  • !Misinterpreting powers: Confusing \(\sin^2 \theta\) with \(\sin \theta^2\), or writing \(\sec^2 \theta\) as \(\dfrac{1}{\sin^2 \theta}\) instead of \(\dfrac{1}{\cos^2 \theta}\).
  • !Treating identities like linear equations during proof: Moving terms across the equals sign (\(=\)) from LHS to RHS before proving they are equal. The LHS and RHS must be handled independently.
  • !Incorrect algebraic cancellations: Cancelling \(\cos \theta\) in expressions like \(\dfrac{1 - \cos^2 \theta}{1 + \cos \theta}\) without factorising first.

Concept Misunderstandings

Misunderstanding

Trigonometric identities are only valid for acute angles between \(0^\circ\) and \(90^\circ\).

Correct Concept

A trigonometric identity is valid for any angle \(\theta\) for which the functions are defined, including obtuse, reflex, and negative angles (e.g., \(\sin^2(-430^\circ) + \cos^2(-430^\circ) = 1\)).

Misunderstanding

You must always work exclusively from the left-hand side to prove an identity.

Correct Concept

You can prove from LHS to RHS, from RHS to LHS, or simplify both LHS and RHS independently to the same final expression.

Summary

  • The three fundamental Pythagoras identities are: \(\sin^2 \theta + \cos^2 \theta = 1\), \(1 + \tan^2 \theta = \sec^2 \theta\), and \(1 + \cot^2 \theta = \text{cosec}^2 \theta\).
  • They are derived by dividing \(a^2 + b^2 = c^2\) by \(c^2\), \(b^2\), and \(a^2\) respectively.
  • Proving identities requires algebraic manipulation, converting to \(\sin\) and \(\cos\), combining fractions, and substituting basic identities without moving terms across the equality sign.

Short Activity

Objective: Test your understanding of basic trigonometric identities and their applications.

A. Objective Quiz

1 Which of the following is equivalent to \(\text{cosec}^2 \theta - \cot^2 \theta\)?

2 What is the result when both sides of Pythagoras' theorem \(a^2 + b^2 = c^2\) are divided by \(b^2\)?

B. Fill in the Blanks

3 Based on the basic trigonometric identities, the numerical value of \(\tan^2 \left(\dfrac{\pi}{3}\right) - \sec^2 \left(\dfrac{\pi}{3}\right)\) is ________.

4 Dividing both sides of the equation \(a^2 + b^2 = c^2\) by \(a^2\) derives the identity \(1 + \cot^2 A =\) ________.

C. Matching / Drag and Drop

Match each trigonometric expression to its simplified equivalent or derived identity. On a phone, tap a term first, then tap the matching box.

Trigonometric Expression
\(\cos^2 80^\circ + \sin^2 80^\circ\)
\(\tan^2 \theta - \sec^2 \theta\)
\(1 - \cos^2 A\)
\(\text{cosec}^2 A - 1\)
\(\sec^2 A - 1\)
\(\tan A + \cot A\)
Equivalent Value or Identity
5\(1\)
6\(-1\)
7\(\sin^2 A\)
8\(\cot^2 A\)
9\(\tan^2 A\)
10\(\sec A \text{ cosec } A\)
Answer key: 1 C; 2 C; 3 -1; 4 cosec^2 A; 5 1; 6 -1; 7 sin^2 A; 8 cot^2 A; 9 tan^2 A; 10 sec A cosec A.

Keywords

Trigonometric identity Basic identities (Pythagoras identities) Secant (sec) Cosecant (cosec) Cotangent (cot) Conjugate

Basic Identities

6.4 Basic Identities - Additional Mathematics Form 5
ADDITIONAL MATHEMATICS • Form 5 • Chapter 6: Trigonometric Functions

6.4 Basic Identities

A trigonometric identity is an equation that involves trigonometric functions and holds true for all valid values of the angle. In this topic, we derive three fundamental Pythagoras identities using right-angled triangles and unit circles: \(\sin^2 \theta + \cos^2 \theta = 1\), \(1 + \tan^2 \theta = \sec^2 \theta\), and \(1 + \cot^2 \theta = \text{cosec}^2 \theta\). We then apply these identities to evaluate trigonometric expressions without using a calculator and to verify and prove various trigonometric identities.

Learning Objectives

  • Derive the three basic trigonometric identities (Pythagoras identities) using a right-angled triangle and Pythagoras' theorem.
  • Use basic trigonometric identities to determine values of expressions without using a calculator.
  • Prove trigonometric identities systematically by simplifying expressions on one or both sides using basic identities, quotient identities, reciprocal identities, or conjugates.

The Hexagon and Division Triangle of Pythagoras Identities

Visualise how the three basic identities connect directly to Pythagoras' theorem \(a^2 + b^2 = c^2\).

From Pythagoras' Theorem to the Three Basic Identities

1

Start with \(a^2 + b^2 = c^2\).

2

Divide by \(c^2\): \(\sin^2 A + \cos^2 A = 1\).

3

Divide by \(b^2\): \(1 + \tan^2 A = \sec^2 A\).

4

Divide by \(a^2\): \(1 + \cot^2 A = \text{cosec}^2 A\).

Identity 1

\(\sin^2 \theta + \cos^2 \theta = 1\)

Divide \(a^2 + b^2 = c^2\) by \(c^2\).

Identity 2

\(1 + \tan^2 \theta = \sec^2 \theta\)

Divide \(a^2 + b^2 = c^2\) by \(b^2\).

Identity 3

\(1 + \cot^2 \theta = \text{cosec}^2 \theta\)

Divide \(a^2 + b^2 = c^2\) by \(a^2\).

Unit Circle Form

\(x^2 + y^2 = 1\)

Where \(x = \cos \theta\) and \(y = \sin \theta\).

Short Explanation

All basic trigonometric identities stem directly from Pythagoras' theorem.

1. Definition and Fundamental Reciprocal & Quotient Identities

A trigonometric identity is an equation involving trigonometric functions that is valid for any values of the angle. Reciprocal and quotient identities: \(\tan \theta = \dfrac{\sin \theta}{\cos \theta}\), \(\cot \theta = \dfrac{1}{\tan \theta} = \dfrac{\cos \theta}{\sin \theta}\), \(\text{cosec } \theta = \dfrac{1}{\sin \theta}\), \(\sec \theta = \dfrac{1}{\cos \theta}\).

2. Derivation of the Three Basic Identities

From a right-angled triangle \(ABC\) with sides \(a\), \(b\), and hypotenuse \(c\) where angle \(A\) is considered: \(\sin A = \dfrac{a}{c}\), \(\cos A = \dfrac{b}{c}\), \(\tan A = \dfrac{a}{b}\), \(\text{cosec } A = \dfrac{c}{a}\), \(\sec A = \dfrac{c}{b}\), \(\cot A = \dfrac{b}{a}\). By Pythagoras' theorem: \(a^2 + b^2 = c^2\).

3. Evaluating Expressions Without a Calculator

Using rearrangement of basic identities: \(\sin^2 (-430^\circ) + \cos^2 (-430^\circ) = 1\) since \(\sin^2 \theta + \cos^2 \theta = 1\) for any angle \(\theta\). Also, \(\tan^2 \left(\dfrac{\pi}{3}\right) - \sec^2 \left(\dfrac{\pi}{3}\right) = -1\) since \(1 + \tan^2 \theta = \sec^2 \theta \implies \tan^2 \theta - \sec^2 \theta = -1\).

4. Proving Trigonometric Identities

Proofs can be done by simplifying the expression on the left-hand side (LHS) until it matches the right-hand side (RHS), simplifying the RHS until it matches the LHS, or simplifying both LHS and RHS independently until both arrive at the exact same simplified expression.

IdentityDerived by dividing \(a^2 + b^2 = c^2\) byRearranged form
\(\sin^2 \theta + \cos^2 \theta = 1\)\(c^2\)\(\sin^2 \theta = 1 - \cos^2 \theta\)
\(1 + \tan^2 \theta = \sec^2 \theta\)\(b^2\)\(\sec^2 \theta - \tan^2 \theta = 1\)
\(1 + \cot^2 \theta = \text{cosec}^2 \theta\)\(a^2\)\(\text{cosec}^2 \theta - \cot^2 \theta = 1\)

Excellent Tips for Proving Identities

1

Prove from the more complex side.

2

Convert expressions to basic trigonometric ratios form (in terms of \(\sin\) and \(\cos\)).

3

Multiply by a conjugate if required, e.g. when terms like \(1 + \cos \theta\) or \(1 - \sin \theta\) appear in denominators.

4

Combine fractions over a common denominator and substitute basic identities directly.

Example 18(a): Prove \(1 - 2\sin^2 A = 2\cos^2 A - 1\)

\(\text{LHS} = 1 - 2(1 - \cos^2 A) = 2\cos^2 A - 1 = \text{RHS}\)

Substitute \(\sin^2 A = 1 - \cos^2 A\).

Example 18(b): Prove \(\tan A + \cot A = \sec A \text{ cosec } A\)

\(\text{LHS} = \dfrac{\sin A}{\cos A} + \dfrac{\cos A}{\sin A} = \dfrac{1}{\cos A \sin A} = \text{RHS}\)

Combine fractions using \(\sin^2 A + \cos^2 A = 1\).

Try to Answer First

Answer in your mind, then press "Check Answer".

1

Without using a calculator, find the value of \(\sec^2 173^\circ - \tan^2 173^\circ\).

2

Given \(\cos \theta = m\), express \(\tan^2 \theta\) in terms of \(m\).

3

Prove the identity: \(\dfrac{\sin^2 \theta}{1 + \cos \theta} = 1 - \cos \theta\).

Common Mistakes

  • !Sign errors when rearranging: Writing \(\tan^2 \theta - \sec^2 \theta = 1\) instead of \(-1\), or \(\cot^2 \theta - \text{cosec}^2 \theta = 1\) instead of \(-1\).
  • !Misinterpreting powers: Confusing \(\sin^2 \theta\) with \(\sin \theta^2\), or writing \(\sec^2 \theta\) as \(\dfrac{1}{\sin^2 \theta}\) instead of \(\dfrac{1}{\cos^2 \theta}\).
  • !Treating identities like linear equations during proof: Moving terms across the equals sign (\(=\)) from LHS to RHS before proving they are equal. The LHS and RHS must be handled independently.
  • !Incorrect algebraic cancellations: Cancelling \(\cos \theta\) in expressions like \(\dfrac{1 - \cos^2 \theta}{1 + \cos \theta}\) without factorising first.

Concept Misunderstandings

Misunderstanding

Trigonometric identities are only valid for acute angles between \(0^\circ\) and \(90^\circ\).

Correct Concept

A trigonometric identity is valid for any angle \(\theta\) for which the functions are defined, including obtuse, reflex, and negative angles (e.g., \(\sin^2(-430^\circ) + \cos^2(-430^\circ) = 1\)).

Misunderstanding

You must always work exclusively from the left-hand side to prove an identity.

Correct Concept

You can prove from LHS to RHS, from RHS to LHS, or simplify both LHS and RHS independently to the same final expression.

Summary

  • The three fundamental Pythagoras identities are: \(\sin^2 \theta + \cos^2 \theta = 1\), \(1 + \tan^2 \theta = \sec^2 \theta\), and \(1 + \cot^2 \theta = \text{cosec}^2 \theta\).
  • They are derived by dividing \(a^2 + b^2 = c^2\) by \(c^2\), \(b^2\), and \(a^2\) respectively.
  • Proving identities requires algebraic manipulation, converting to \(\sin\) and \(\cos\), combining fractions, and substituting basic identities without moving terms across the equality sign.

Short Activity

Objective: Test your understanding of basic trigonometric identities and their applications.

A. Objective Quiz

1 Which of the following is equivalent to \(\text{cosec}^2 \theta - \cot^2 \theta\)?

2 What is the result when both sides of Pythagoras' theorem \(a^2 + b^2 = c^2\) are divided by \(b^2\)?

B. Fill in the Blanks

3 Based on the basic trigonometric identities, the numerical value of \(\tan^2 \left(\dfrac{\pi}{3}\right) - \sec^2 \left(\dfrac{\pi}{3}\right)\) is ________.

4 Dividing both sides of the equation \(a^2 + b^2 = c^2\) by \(a^2\) derives the identity \(1 + \cot^2 A =\) ________.

C. Matching / Drag and Drop

Match each trigonometric expression to its simplified equivalent or derived identity. On a phone, tap a term first, then tap the matching box.

Trigonometric Expression
\(\cos^2 80^\circ + \sin^2 80^\circ\)
\(\tan^2 \theta - \sec^2 \theta\)
\(1 - \cos^2 A\)
\(\text{cosec}^2 A - 1\)
\(\sec^2 A - 1\)
\(\tan A + \cot A\)
Equivalent Value or Identity
5\(1\)
6\(-1\)
7\(\sin^2 A\)
8\(\cot^2 A\)
9\(\tan^2 A\)
10\(\sec A \text{ cosec } A\)
Answer key: 1 C; 2 C; 3 -1; 4 cosec^2 A; 5 1; 6 -1; 7 sin^2 A; 8 cot^2 A; 9 tan^2 A; 10 sec A cosec A.

Keywords

Trigonometric identity Basic identities (Pythagoras identities) Secant (sec) Cosecant (cosec) Cotangent (cot) Conjugate