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SOLUTION: \(\frac{3}{4}\div6=\)
So, each part will be \(\frac{1}{8}\). |
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SOLUTION: \(2\frac{1}{4}\div3=\)
So, the length of each ribbon cut is \(\frac{3}{4}\text{ m}\). |
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SOLUTION: \(\frac{1}{2}\div\frac{1}{4}=\) \(\frac{1}{2}\div\frac{1}{4}\\\,\\=\frac{1}{2}\times\frac{4}{1}\\\,\\=\frac{4}{2}\\\,\\=2\) So, the number of trials is 2. |
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SOLUTION: \(1\frac{1}{2}\div\frac{1}{4}=\) \(\;\;\;1\frac{1}{2}\div\frac{1}{4}\\\,\\=\frac{3}{2}\times\frac{4}{1}\\\,\\=\frac{12}{2}\\\,\\=6\) So, there are 6 parts of a \(\frac{1}{4}\text{ kg}\) in \(1\frac{1}{2}\) kg. |
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2.2
Fractions
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