Science Chapter 11: Force and Motion
11.2 Linear Motion Graphs
11.2 Linear Motion Graphs
SCIENCE • Form 4 • Chapter 11: Force and Motion

11.2 Linear Motion Graphs

Learn to interpret displacement-time and velocity-time graphs and calculate velocity, acceleration, and displacement from gradients and areas.

Learning Objectives

  • State the two types of linear motion graphs: displacement-time graph and velocity-time graph.
  • Explain the meaning of gradient and area under linear motion graphs.
  • Interpret the motion of an object from displacement-time and velocity-time graphs.
  • Solve numerical problems involving displacement-time and velocity-time graphs.

Summary of Linear Motion Graphs and Their Physical Quantities

Compare displacement-time and velocity-time graphs side by side to understand what gradients and areas represent.

Comparison of displacement-time and velocity-time graphs A two-column diagram comparing a displacement-time graph and a velocity-time graph. The left column shows a rising line, a flat horizontal line, and a falling line, labelled with gradient equals velocity, object at rest, and moving back in the opposite direction. The right column shows a rising line, a flat horizontal line above the time axis, and a falling line, labelled with gradient equals acceleration, area under graph equals displacement, uniform velocity with zero acceleration, and uniform deceleration. Displacement-time graph Velocity-time graph Time Time Displacement Velocity Gradient = velocity Horizontal line = object at rest Downward slope = moving back Gradient = acceleration Area under graph = displacement Horizontal line above axis = uniform velocity Downward slope = uniform deceleration

Displacement-Time Graph

Gradient = Velocity

Horizontal line = Object at rest (zero velocity).

Negative gradient = Moving in the opposite direction / moving back.

Velocity-Time Graph

Gradient = Acceleration

Area under graph = Displacement

Horizontal line = Constant velocity (zero acceleration).

Short Explanation

What are linear motion graphs?

Linear motion graphs translate numerical data into visual representations. There are two types: the displacement-time graph and the velocity-time graph.

In a displacement-time graph, the vertical axis shows position and the horizontal axis shows time. The slope or gradient tells us the velocity of the object. A flat horizontal line means the position is not changing, so the object is at rest. A negative gradient means the object is travelling in the reverse direction back toward the starting point.

In a velocity-time graph, the vertical axis shows velocity. The slope or gradient indicates acceleration. A flat horizontal line does not mean the object is stationary; it means the object travels at a constant velocity with zero acceleration. To find total displacement from a velocity-time graph, calculate the total geometric area under the graph between the graph line and the time axis.

Key relationships

For a displacement-time graph: \(\text{Gradient} = \text{velocity}\).

For a velocity-time graph: \(\text{Gradient} = \text{acceleration}\) and \(\text{Area under graph} = \text{displacement}\).

Displacement-Time Graph

The gradient of a displacement-time graph represents velocity.

A displacement-time graph shows how the displacement of an object changes with time. The gradient of the graph gives the velocity of the object:

\[\text{Velocity} = \dfrac{\Delta s}{\Delta t} = \dfrac{s_2 - s_1}{t_2 - t_1}\]

Interpreting the sections of a displacement-time graph.
Section Gradient Motion of the object
OA Positive, uniform Velocity is uniform; the object moves away from the starting point with uniform speed.
AB Zero (horizontal line) Velocity is zero; the object is at rest (stationary).
BC Positive, uniform Velocity is uniform; the object continues moving forward with uniform speed.
CD Negative, uniform Velocity is negative and uniform; the object is moving in the opposite direction, turning back towards the starting point with uniform speed.
Curve with decreasing gradient Decreasing Velocity is decreasing; the object is decelerating or slowing down.
Displacement-time graph of the motion of a boy from point O The displacement-time graph shows a boy moving 50 m in the first 2 seconds (OA), at rest from the 2nd to the 8th second (AB), moving forward another 50 m from the 8th to the 12th second (BC), and turning back 100 m to the starting point from the 12th to the 16th second (CD). O A B C D 2 4 6 8 10 12 14 16 50 100 Time (s) Displacement (m)

Worked example: finding velocity

From the 3rd to the 5th second, the displacement changes from \(4\ \text{m}\) to \(8\ \text{m}\).

\[\text{Velocity} = \dfrac{(8 - 4)\ \text{m}}{(5 - 3)\ \text{s}} = \dfrac{4\ \text{m}}{2\ \text{s}} = 2\ \text{m s}^{-1}\]

From the 6th to the 12th second, the displacement changes from \(15\ \text{m}\) to \(0\ \text{m}\).

\[\text{Velocity} = \dfrac{(0 - 15)\ \text{m}}{(12 - 6)\ \text{s}} = \dfrac{-15\ \text{m}}{6\ \text{s}} = -2.5\ \text{m s}^{-1}\]

The negative sign indicates motion in the opposite direction.

Velocity-Time Graph

The gradient gives acceleration, and the area under the graph gives displacement.

A velocity-time graph shows how the velocity of an object changes with time. It allows displacement, velocity and acceleration to be determined.

\[\text{Acceleration} = \dfrac{\Delta v}{\Delta t} = \dfrac{v_2 - v_1}{t_2 - t_1}\]

\[\text{Displacement} = \text{area under the velocity-time graph}\]

Interpreting the sections of a velocity-time graph.
Section Gradient Motion of the object
OA Positive, uniform Velocity increases uniformly; acceleration is uniform.
AB Zero, velocity above time axis Velocity is constant; acceleration is zero.
BC Negative, uniform Velocity decreases uniformly; the object moves with negative acceleration or uniform deceleration.
CD Zero, on the time axis Velocity is zero; the object is stationary. Acceleration is zero.
Velocity-time graph of the motion of a motorcycle from point O The velocity-time graph shows a motorcycle accelerating uniformly to 8 m s-1 in the first 5 seconds (OA), moving at a constant velocity of 8 m s-1 from the 5th to the 15th second (AB), decelerating uniformly until it stops at the 20th second (BC), and remaining stationary afterwards (CD on the time axis). O A B C D 5 10 15 20 8 Time (s) Velocity (m s⁻¹)

Worked example: finding acceleration

From the 8th to the 12th second, the velocity changes from \(3\ \text{m s}^{-1}\) to \(0\ \text{m s}^{-1}\).

\[\text{Acceleration} = \dfrac{(0 - 3)\ \text{m s}^{-1}}{(12 - 8)\ \text{s}} = \dfrac{-3\ \text{m s}^{-1}}{4\ \text{s}} = -0.75\ \text{m s}^{-2}\]

Worked example: finding displacement

In the first 4 seconds, the area under the graph is a rectangle:

\[\text{Displacement} = 4\ \text{s} \times 1\ \text{m s}^{-1} = 4\ \text{m}\]

Between 0 and 10 seconds, the area is a triangle plus a rectangle:

\[\text{Displacement} = \left[\dfrac{1}{2} \times (6\ \text{s})(15\ \text{m s}^{-1})\right] + \left[(10\ \text{s} - 6\ \text{s})(15\ \text{m s}^{-1})\right] = 45\ \text{m} + 60\ \text{m} = 105\ \text{m}\]

Try to Answer First

Answer in your mind, then press “Check Answer”.

1

What physical quantity is represented by the gradient of a displacement-time graph?

Answer: Velocity.
2

What does a horizontal line above the time axis represent in a velocity-time graph?

Answer: Constant velocity (or uniform velocity) with zero acceleration.
3

How do you determine the displacement of an object from a velocity-time graph?

Answer: By calculating the area under the velocity-time graph.

Common Mistakes

  • !Confusing the meaning of a horizontal line: mistaking a horizontal line in a velocity-time graph for an object at rest. A horizontal line in a velocity-time graph means constant velocity, not stationary.
  • !Calculating the area under a displacement-time graph. The area under a displacement-time graph does not represent any meaningful physical quantity in Form 4 Science.
  • !Forgetting negative signs: omitting the negative sign when calculating a negative gradient, which represents negative velocity or deceleration.
  • !Writing incorrect units: confusing the unit of velocity, \(\text{m s}^{-1}\), with acceleration, \(\text{m s}^{-2}\).

Concept Misunderstandings

Misconception

A negative gradient on a displacement-time graph means the object is decelerating.

Correct Concept

A negative gradient on a displacement-time graph means the object has a negative velocity, indicating that it is moving in the opposite direction, returning towards the reference or starting point.

Misconception

A horizontal line on any motion graph means the object has stopped moving.

Correct Concept

On a displacement-time graph, a horizontal line means displacement is constant, so velocity is zero and the object is stationary. On a velocity-time graph, a horizontal line means velocity is maintained at a non-zero constant value, so the object is moving with zero acceleration.

Summary

  • Linear motion graphs consist of displacement-time graphs and velocity-time graphs.
  • For a displacement-time graph, the gradient represents velocity in \(\text{m s}^{-1}\). A horizontal line indicates that the object is at rest, and a negative gradient indicates motion in the opposite direction.
  • For a velocity-time graph, the gradient represents acceleration in \(\text{m s}^{-2}\), and the area under the graph represents displacement in \(\text{m}\).
  • A horizontal line on a velocity-time graph indicates constant velocity with zero acceleration, while a downward slope represents negative acceleration or deceleration.

Short Activity

A. Objective Quiz

1 What does the gradient of a velocity-time graph represent?

2 Based on a displacement-time graph, what is the state of motion of an object when the line is horizontal?

B. Fill in the Blanks

3 The displacement of an object can be determined by calculating the under a velocity-time graph.

 

4 A negative gradient on a displacement-time graph indicates that the object is moving in the direction.

 

C. Drag and Drop: Match the Graph Feature to Its Representation

Drag each graph feature to the physical quantity or motion state it represents. On a phone, tap an answer first, then tap a matching box. Tap the Answer Choices area to return a selected item.

Graph Feature
Gradient of displacement-time graph
Gradient of velocity-time graph
Area under velocity-time graph
Zero gradient on velocity-time graph
Representation
1 Velocity of the moving object
2 Acceleration of the moving object
3 Displacement travelled by the object
4 Motion with constant velocity and zero acceleration

C. Match the Graph Feature to Its Representation

Write the correct graph feature next to each representation.

Representation Graph Feature
1. Velocity of the moving object  
2. Acceleration of the moving object  
3. Displacement travelled by the object  
4. Motion with constant velocity and zero acceleration  

Answer choices: Gradient of displacement-time graph • Gradient of velocity-time graph • Area under velocity-time graph • Zero gradient on velocity-time graph

Keywords

Displacement-time graph Velocity-time graph Gradient Area under the graph Deceleration At rest