Speed-Time Graphs

7.2 Speed-Time Graphs — Mathematics Form 4
MATHEMATICS • Form 4 • Chapter 7: Graphs of Motion

7.2 Speed-Time Graphs

A speed-time graph represents the motion of an object by showing how its speed changes over time. On this graph, the vertical axis represents speed, while the horizontal axis represents the time taken. The gradient of the graph represents the rate of change of speed with respect to time (acceleration or deceleration), and the area under the graph represents the total distance travelled by the object.

Learning Objectives

  • Draw speed-time graphs based on a given speed-time table or a mathematical equation.
  • Make a relationship between the area under a speed-time graph and the distance travelled, and hence determine the distance.
  • Interpret speed-time graphs and describe the movement of an object based on the graphs.
  • Solve problems involving speed-time graphs, including calculating acceleration, deceleration, uniform speed, distance travelled, and average speed.

Key Components of a Speed-Time Graph

See how acceleration, uniform speed, deceleration and distance travelled are represented on one graph.

Time, t (s) Speed, v (m s⁻¹) O P Q R A B C Acceleration Positive gradient Uniform Speed Zero gradient Deceleration Negative gradient Area under graph = Distance travelled

Brief Explanation

What is a speed-time graph?

A speed-time graph shows how an object's speed changes as time progresses. The vertical axis represents speed, \(v\), and the horizontal axis represents time, \(t\).

What does the gradient represent?

The gradient of a speed-time graph represents the rate of change of speed with respect to time, which is acceleration.

Acceleration formula

\[\text{Acceleration} = \dfrac{\text{Change of speed}}{\text{Change in time}}\]

Drawing from a speed-time table

Choose appropriate scales for both axes, plot the coordinate points \((t, v)\), then join the points using a ruler or a smooth curve.

Drawing from an equation

Construct a speed-time table by calculating speed values for given time intervals, then plot the points and join them.

Area under the graph

The area under the graph equals the distance travelled. Common shapes are rectangles, triangles and trapeziums.

\[\text{Area under speed-time graph} = \text{Distance travelled}\]

Shape Area formula Use on a speed-time graph
Rectangle \(\text{length} \times \text{width}\) Distance travelled at uniform speed
Triangle \(\frac{1}{2} \times \text{base} \times \text{height}\) Distance travelled during acceleration or deceleration
Trapezium \(\frac{1}{2} \times (\text{sum of parallel sides}) \times \text{height}\) Distance travelled when speed changes between two non-zero values
1
Positive gradient
Speed increases. Acceleration is positive. The area under this segment represents distance travelled during acceleration.
2
Zero gradient
Speed remains constant. The object moves at uniform speed. Acceleration is \(0\text{ m s}^{-2}\).
3
Negative gradient
Speed decreases. The rate of change of speed is negative. Deceleration is positive when stated as deceleration.

Average speed

\[\text{Average speed} = \dfrac{\text{Total distance}}{\text{Total time}}\]

Try Answering First

Read the question, answer it in your mind, then press “Check Answer”.

1

A car accelerates uniformly from rest to a speed of \(20\text{ m s}^{-1}\) in \(5\text{ seconds}\). What is its acceleration?

Answer: \(\text{Acceleration} = \dfrac{20 - 0}{5 - 0} = 4\text{ m s}^{-2}\).
2

What does the area under a speed-time graph represent?

Answer: The distance travelled by the moving object.
3

A motorcycle travels at a uniform speed of \(15\text{ m s}^{-1}\) for \(8\text{ seconds}\). Calculate the distance travelled during this period.

Answer: \(\text{Distance} = \text{speed} \times \text{time} = 15\text{ m s}^{-1} \times 8\text{ s} = 120\text{ m}\).

Area Under the Graph and Distance

Calculating distance from the area under a scaled speed-time graph, step by step.

The area under a speed-time graph is the distance travelled

For a speed-time graph, the area under the graph = the distance travelled over the same time interval. Split the area into triangles, rectangles and trapeziums, work out each area, then add them.

Make sure the time unit in the speed matches the unit on the time axis before calculating.

A scaled example

The graph below shows the motion of a car over 15 seconds. Calculate (a) the rate of change of speed for the first 5 seconds, (b) describe the motion for the second 5 seconds, and (c) the total distance travelled.

A B C 5 10 15 20 40 60 O Time (seconds) Speed (m s⁻¹) accelerating uniform speed accelerating

The area under the graph is divided into trapezium \(A\), rectangle \(B\) and trapezium \(C\).

1
(a) Rate of change of speed, first 5 seconds
Gradient \(= \dfrac{40 - 20}{5 - 0} = \dfrac{20}{5} = 4\) m s\(^{-2}\). The car is accelerating at 4 m s\(^{-2}\).
2
(b) Motion for the second 5 seconds
From \(t = 5\) s to \(t = 10\) s the gradient is zero — the car moves at a uniform speed of 40 m s\(^{-1}\) for 5 seconds.
3
(c) Area \(A\): trapezium
\(A = \tfrac{1}{2} \times 5 \times (20 + 40) = \tfrac{1}{2} \times 5 \times 60 = 150\) m.
4
(c) Area \(B\): rectangle
\(B = (10 - 5) \times 40 = 5 \times 40 = 200\) m.
5
(c) Area \(C\): trapezium
\(C = \tfrac{1}{2} \times 5 \times (40 + 60) = \tfrac{1}{2} \times 5 \times 100 = 250\) m.
6
(c) Total distance
Total distance \(= 150 + 200 + 250 = \mathbf{600}\) m. Average speed \(= \dfrac{600}{15} = 40\) m s\(^{-1}\).

Be careful with rounding

If an answer has to be rounded, use the exact value in any later calculation, not the rounded one. For example, if the exact total distance is \(\dfrac{454}{15} = 30.2\overline{6}\) km and is rounded to \(30.27\) km, then the average speed over 36 minutes is \(\dfrac{454/15}{0.6} = 50.44\) km h\(^{-1}\) — not the \(30.27 \div 0.6 = 50.45\) km h\(^{-1}\) you get from the rounded value.

Common Mistakes

  • !Forgetting to convert time units when calculating distance. For example, multiplying speed in \(\text{km h}^{-1}\) directly by time in minutes without dividing by \(60\).
  • !Confusing distance-time graphs with speed-time graphs. A horizontal flat line on a speed-time graph means uniform speed, not stationary.
  • !Writing negative values when asked for “deceleration”. Write acceleration \(= -2\text{ m s}^{-2}\) or deceleration \(= 2\text{ m s}^{-2}\), not deceleration \(= -2\text{ m s}^{-2}\).
  • !Misidentifying the parallel sides when applying the trapezium area formula \(\frac{1}{2}(a + b)h\).

Misconceptions

Misconception

A negative gradient means the object is moving backwards or in the opposite direction.

Correct Fact

The object is still moving forward in the same direction; only its speed is decreasing (decelerating).

Misconception

A speed of zero means the graph stops.

Correct Fact

A speed of zero means the object is momentarily stationary; time continues to increase along the horizontal axis.

Summary

  • The vertical axis represents speed, and the horizontal axis represents time.
  • The gradient of a speed-time graph gives the acceleration (rate of change of speed).
  • A horizontal line (gradient \(= 0\)) represents motion at uniform speed.
  • The area under the graph equals the distance travelled.
  • Average speed is determined by dividing the total distance by the total time.

Short Activity

Complete all parts first, then press the check answer button.

A. Objective Quiz

1 What does the gradient of a speed-time graph represent?

2 A car travels with a speed that decreases from \(25\text{ m s}^{-1}\) to \(0\text{ m s}^{-1}\) in \(5\text{ seconds}\). What is its deceleration?

B. Fill in the Blanks

3 The total distance travelled by an object is determined by calculating the under its speed-time graph.

4 On a speed-time graph, a horizontal straight line with zero gradient indicates that the object is moving at a speed.

C. Drag and Drop: Match Graph Features to Their Meanings

Drag each graph feature to the correct physical meaning. On a phone, tap the answer choice first, then tap the meaning box.

Graph Feature
Positive gradient
Zero gradient
Negative gradient
Area under the graph
Physical Meaning
The object is accelerating (speed is increasing) Correct Try again Empty
The object moves at a uniform speed Correct Try again Empty
The object is decelerating (speed is decreasing) Correct Try again Empty
Represents the total distance travelled Correct Try again Empty
 

Key Terms

Speed-time graph Acceleration Deceleration Uniform speed Area under the graph Average speed

Speed-Time Graphs

7.2 Speed-Time Graphs — Mathematics Form 4
MATHEMATICS • Form 4 • Chapter 7: Graphs of Motion

7.2 Speed-Time Graphs

A speed-time graph represents the motion of an object by showing how its speed changes over time. On this graph, the vertical axis represents speed, while the horizontal axis represents the time taken. The gradient of the graph represents the rate of change of speed with respect to time (acceleration or deceleration), and the area under the graph represents the total distance travelled by the object.

Learning Objectives

  • Draw speed-time graphs based on a given speed-time table or a mathematical equation.
  • Make a relationship between the area under a speed-time graph and the distance travelled, and hence determine the distance.
  • Interpret speed-time graphs and describe the movement of an object based on the graphs.
  • Solve problems involving speed-time graphs, including calculating acceleration, deceleration, uniform speed, distance travelled, and average speed.

Key Components of a Speed-Time Graph

See how acceleration, uniform speed, deceleration and distance travelled are represented on one graph.

Time, t (s) Speed, v (m s⁻¹) O P Q R A B C Acceleration Positive gradient Uniform Speed Zero gradient Deceleration Negative gradient Area under graph = Distance travelled

Brief Explanation

What is a speed-time graph?

A speed-time graph shows how an object's speed changes as time progresses. The vertical axis represents speed, \(v\), and the horizontal axis represents time, \(t\).

What does the gradient represent?

The gradient of a speed-time graph represents the rate of change of speed with respect to time, which is acceleration.

Acceleration formula

\[\text{Acceleration} = \dfrac{\text{Change of speed}}{\text{Change in time}}\]

Drawing from a speed-time table

Choose appropriate scales for both axes, plot the coordinate points \((t, v)\), then join the points using a ruler or a smooth curve.

Drawing from an equation

Construct a speed-time table by calculating speed values for given time intervals, then plot the points and join them.

Area under the graph

The area under the graph equals the distance travelled. Common shapes are rectangles, triangles and trapeziums.

\[\text{Area under speed-time graph} = \text{Distance travelled}\]

Shape Area formula Use on a speed-time graph
Rectangle \(\text{length} \times \text{width}\) Distance travelled at uniform speed
Triangle \(\frac{1}{2} \times \text{base} \times \text{height}\) Distance travelled during acceleration or deceleration
Trapezium \(\frac{1}{2} \times (\text{sum of parallel sides}) \times \text{height}\) Distance travelled when speed changes between two non-zero values
1
Positive gradient
Speed increases. Acceleration is positive. The area under this segment represents distance travelled during acceleration.
2
Zero gradient
Speed remains constant. The object moves at uniform speed. Acceleration is \(0\text{ m s}^{-2}\).
3
Negative gradient
Speed decreases. The rate of change of speed is negative. Deceleration is positive when stated as deceleration.

Average speed

\[\text{Average speed} = \dfrac{\text{Total distance}}{\text{Total time}}\]

Try Answering First

Read the question, answer it in your mind, then press “Check Answer”.

1

A car accelerates uniformly from rest to a speed of \(20\text{ m s}^{-1}\) in \(5\text{ seconds}\). What is its acceleration?

Answer: \(\text{Acceleration} = \dfrac{20 - 0}{5 - 0} = 4\text{ m s}^{-2}\).
2

What does the area under a speed-time graph represent?

Answer: The distance travelled by the moving object.
3

A motorcycle travels at a uniform speed of \(15\text{ m s}^{-1}\) for \(8\text{ seconds}\). Calculate the distance travelled during this period.

Answer: \(\text{Distance} = \text{speed} \times \text{time} = 15\text{ m s}^{-1} \times 8\text{ s} = 120\text{ m}\).

Area Under the Graph and Distance

Calculating distance from the area under a scaled speed-time graph, step by step.

The area under a speed-time graph is the distance travelled

For a speed-time graph, the area under the graph = the distance travelled over the same time interval. Split the area into triangles, rectangles and trapeziums, work out each area, then add them.

Make sure the time unit in the speed matches the unit on the time axis before calculating.

A scaled example

The graph below shows the motion of a car over 15 seconds. Calculate (a) the rate of change of speed for the first 5 seconds, (b) describe the motion for the second 5 seconds, and (c) the total distance travelled.

A B C 5 10 15 20 40 60 O Time (seconds) Speed (m s⁻¹) accelerating uniform speed accelerating

The area under the graph is divided into trapezium \(A\), rectangle \(B\) and trapezium \(C\).

1
(a) Rate of change of speed, first 5 seconds
Gradient \(= \dfrac{40 - 20}{5 - 0} = \dfrac{20}{5} = 4\) m s\(^{-2}\). The car is accelerating at 4 m s\(^{-2}\).
2
(b) Motion for the second 5 seconds
From \(t = 5\) s to \(t = 10\) s the gradient is zero — the car moves at a uniform speed of 40 m s\(^{-1}\) for 5 seconds.
3
(c) Area \(A\): trapezium
\(A = \tfrac{1}{2} \times 5 \times (20 + 40) = \tfrac{1}{2} \times 5 \times 60 = 150\) m.
4
(c) Area \(B\): rectangle
\(B = (10 - 5) \times 40 = 5 \times 40 = 200\) m.
5
(c) Area \(C\): trapezium
\(C = \tfrac{1}{2} \times 5 \times (40 + 60) = \tfrac{1}{2} \times 5 \times 100 = 250\) m.
6
(c) Total distance
Total distance \(= 150 + 200 + 250 = \mathbf{600}\) m. Average speed \(= \dfrac{600}{15} = 40\) m s\(^{-1}\).

Be careful with rounding

If an answer has to be rounded, use the exact value in any later calculation, not the rounded one. For example, if the exact total distance is \(\dfrac{454}{15} = 30.2\overline{6}\) km and is rounded to \(30.27\) km, then the average speed over 36 minutes is \(\dfrac{454/15}{0.6} = 50.44\) km h\(^{-1}\) — not the \(30.27 \div 0.6 = 50.45\) km h\(^{-1}\) you get from the rounded value.

Common Mistakes

  • !Forgetting to convert time units when calculating distance. For example, multiplying speed in \(\text{km h}^{-1}\) directly by time in minutes without dividing by \(60\).
  • !Confusing distance-time graphs with speed-time graphs. A horizontal flat line on a speed-time graph means uniform speed, not stationary.
  • !Writing negative values when asked for “deceleration”. Write acceleration \(= -2\text{ m s}^{-2}\) or deceleration \(= 2\text{ m s}^{-2}\), not deceleration \(= -2\text{ m s}^{-2}\).
  • !Misidentifying the parallel sides when applying the trapezium area formula \(\frac{1}{2}(a + b)h\).

Misconceptions

Misconception

A negative gradient means the object is moving backwards or in the opposite direction.

Correct Fact

The object is still moving forward in the same direction; only its speed is decreasing (decelerating).

Misconception

A speed of zero means the graph stops.

Correct Fact

A speed of zero means the object is momentarily stationary; time continues to increase along the horizontal axis.

Summary

  • The vertical axis represents speed, and the horizontal axis represents time.
  • The gradient of a speed-time graph gives the acceleration (rate of change of speed).
  • A horizontal line (gradient \(= 0\)) represents motion at uniform speed.
  • The area under the graph equals the distance travelled.
  • Average speed is determined by dividing the total distance by the total time.

Short Activity

Complete all parts first, then press the check answer button.

A. Objective Quiz

1 What does the gradient of a speed-time graph represent?

2 A car travels with a speed that decreases from \(25\text{ m s}^{-1}\) to \(0\text{ m s}^{-1}\) in \(5\text{ seconds}\). What is its deceleration?

B. Fill in the Blanks

3 The total distance travelled by an object is determined by calculating the under its speed-time graph.

4 On a speed-time graph, a horizontal straight line with zero gradient indicates that the object is moving at a speed.

C. Drag and Drop: Match Graph Features to Their Meanings

Drag each graph feature to the correct physical meaning. On a phone, tap the answer choice first, then tap the meaning box.

Graph Feature
Positive gradient
Zero gradient
Negative gradient
Area under the graph
Physical Meaning
The object is accelerating (speed is increasing) Correct Try again Empty
The object moves at a uniform speed Correct Try again Empty
The object is decelerating (speed is decreasing) Correct Try again Empty
Represents the total distance travelled Correct Try again Empty
 

Key Terms

Speed-time graph Acceleration Deceleration Uniform speed Area under the graph Average speed