The radius of a circle that intersects with the tangent to the circle at the point of tangency will form a \(90{^\circ}\) angle with the tangent.
The following diagram shows a circle with centre \(O\) which meets the straight line \(ABC\) at point \(B\) only.
Calculate the value of \(x\).
Line \(ABC\) is a tangent to the circle and it touches the circle at point \(B\).
So, \(\angle OBA=90{^\circ}\)
\(\begin{aligned}\\ \angle AOB + 138{^\circ}&= 180 {^\circ} \\\\\angle AOB&= 180 {^\circ} - 138{^\circ} \\\\&=42{^\circ}.\\\\ \end{aligned}\)
\(\begin{aligned} x + \angle AOB&= 90 {^\circ} \\\\x&= 90{^\circ} - \angle AOB \\\\x&=90{^\circ} - 42{^\circ} \\\\x&=48.{^\circ} \end{aligned}\)
If two tangents to a circle with centre \(O\) and points of tangency \(B\) and \(C\) meet at point \(A\), then
\(\angle x=\angle y\) and \(\angle \theta=\angle \beta\) because the angles between the chords and the tangents are equal to the angles at the alternate segments subtended by the chords.
Treat yourself with rewards for your hard work