Additional Mathematics Chapter 3: Integration
3.4 Application of Integration
3.4 Application of Integration
ADDITIONAL MATHEMATICS • Form 5 • Chapter 3: Integration

3.4 Application of Integration

Integration is a branch of calculus with wide applications in daily life, science, and industry. By using definite and indefinite integration, we can find areas under curves, calculate volumes of revolution for real-world objects, determine quantities from given rates of change, and solve problems in fields such as engineering, economics, and biology.

Learning Objectives

  • Apply integration to calculate the internal volume of three-dimensional objects formed by revolving a curve.
  • Formulate and evaluate definite integrals from given rate-of-change functions, such as bacterial colony growth rates or production rates.
  • Apply the four-step mathematical problem-solving model (Understanding the problem, Planning the strategy, Implementing the strategy, Check and reflect) to solve real-world integration problems.

The 4-Step Mathematical Problem-Solving Cycle in Integration

Illustrate how real-world problems are broken down, translated into calculus operations, and verified.

From Real Object to Verified Solution

1

Identify dimensions / rate equations from real object.

2

Choose integration method: \(\int \pi x^2 \, dy\) for volume, \(\int \frac{dA}{dt} \, dt\) for total change.

3

Evaluate definite integral and apply scale factors (e.g., cell density or unit cost).

4

Check solution by reversing the equation.

Short Explanation

Integration serves as an accumulation tool for real-world quantities.

1. Areas of Regions Bounded by Curves

Definite integrals calculate the area between a curve and the \(x\)-axis or between two curves.

2. Distance from Velocity Function

Integrating a velocity function over time gives the total distance moved by an object.

3. Rate-of-Change Problems

Used in economics, biology, statistics, and engineering. Given \(\frac{dA}{dt}\) or \(\frac{dK}{dt}\), integrate over an interval to find the net accumulated quantity.

4. Generated Volumes of Revolution

For a curved profile such as \(y = ax^2\), the internal volume is found by revolving the curve around an axis.

Application Integral Form Meaning
Volume of revolution about \(y\)-axis \(\int_{a}^{b} \pi x^2 \, dy\) Internal volume of a 3D object with curved profile.
Accumulated change from rate \(\int_{t_1}^{t_2} \frac{dA}{dt} \, dt\) Net change in quantity over time interval.
Total production \(\int_{t_1}^{t_2} \frac{dK}{dt} \, dt\) Total quantity produced by a machine.

Four-Step Problem-Solving Framework

1

Understanding the problem: Identify given variables, constants, boundaries, units, and what needs to be determined.

2

Planning the strategy: Formulate equations, identify coordinates of boundary points, select appropriate integration formulas.

3

Implementing the strategy: Substitute known values, set up definite integrals with proper limits, integrate, evaluate, and compute final quantities with proper units.

4

Check and reflect: Verify the result using an alternative method, such as solving backward for the initial parameters.

Internal volume of revolution about \(y\)-axis

\(V = \int_{a}^{b} \pi x^2 \, dy\)

Express \(x^2\) in terms of \(y\) before integrating.

Accumulated quantity from rate of change

\(A = \int_{t_1}^{t_2} \frac{dA}{dt} \, dt\)

Integrate the rate function over the time interval.

Try to Answer First

Answer in your mind, then press "Check Answer".

1

The cross-section of a container is represented by \(y = ax^2\). If the diameter is \(12\text{ cm}\) when the depth is \(2\text{ cm}\), what is the value of \(a\)?

2

If the area of a bacterial culture grows at the rate \(\frac{dA}{dt} = 2t + 5\text{ cm}^2/\text{s}\), what is the total area formed from \(t = 0\) to \(t = 5\text{ seconds}\)?

3

Using the area of \(50\text{ cm}^2\) from Question 2, find the number of bacteria cells present if the cell density is \(1\,000\,000\text{ cells/cm}^2\).

Common Mistakes

  • !Using diameter instead of radius when substituting coordinates into equations like \(y = ax^2\) (e.g., using \(x = 12\) instead of \(x = 6\)).
  • !Forgetting \(\pi\) when calculating the volume of revolution of a parabolic cross-section.
  • !Integrating with respect to the wrong variable, such as using \(dx\) instead of \(dy\) when revolving around the \(y\)-axis.
  • !Neglecting the constant factor or density multiplier at the end of an accumulation problem (e.g., finding only the area \(50\text{ cm}^2\) and omitting the multiplication by \(1\,000\,000\text{ cells/cm}^2\)).

Concept Misunderstandings

Misunderstanding

Thinking that the derivative gives total quantity, rather than the instantaneous rate of change.

Correct Concept

The derivative gives the instantaneous rate of change; to find the accumulated total, integration must be applied.

Misunderstanding

Assuming the limits of integration for volume must always start at the origin on the \(x\)-axis.

Correct Concept

For rotation about the \(y\)-axis, the limits must be taken along the \(y\)-axis (depth values).

Misunderstanding

Believing that the "Check and reflect" stage is merely re-reading the question.

Correct Concept

It requires active algebraic or numerical verification, such as solving backward.

Summary

  • Applications of integration involve translating a physical or biological scenario into a calculus model.
  • By setting up a definite integral of a rate function over time, we obtain the net change in a quantity.
  • By setting up a definite integral of \(\pi x^2 \, dy\) over the vertical limits of a curved cross-section, we calculate the internal volume of three-dimensional symmetrical objects.
  • The four-step problem-solving model provides a structured approach: understand, plan, implement, and check/reflect.

Short Activity

Objective: Apply integration to volumes, rates of change, and the four-step problem-solving model.

A. Objective Quiz

1 The cross-section of a bowl is modelled by \(y = \frac{1}{18}x^2\). What is the internal volume of the bowl, in \(\text{cm}^3\), if its depth is \(2\text{ cm}\)?

2 The rate of change of the area of a bacterial culture is given by \(\frac{dA}{dt} = 2t + 5\). What is the increase in area from \(t = 0\) to \(t = 5\text{ seconds}\)?

B. Fill in the Blanks

3 If a parabolic bowl has depth \(2\text{ cm}\) and diameter \(12\text{ cm}\) with equation \(y = ax^2\), the value of the constant \(a\) is ____.

4 When finding the total accumulated change of a quantity from its rate of change \(\frac{dA}{dt}\) over the interval \(t = 0\) to \(t = 5\), the mathematical operation used is ____ integration.

C. Matching / Drag and Drop

Match each step of the four-step problem-solving model or integration concept to its corresponding description or example from the textbook. Drag each term to the correct meaning. On a phone, tap a term first, then tap the matching box.

Concept / Step
Understanding the problem
Planning the strategy
Implementing the strategy
Check and reflect
Rate of growth \(\frac{dA}{dt}\)
\(\int_{0}^{5} (2t + 5) \, dt\)
Description / Mathematical Action
5Identify the diameter (\(12\text{ cm}\)), depth (\(2\text{ cm}\)), and equation of curve (\(y = ax^2\)).
6Substitute coordinate \((6, 2)\) into \(y = ax^2\) and use \(\int_{0}^{2} \pi x^2 \, dy\).
7Evaluate \(\pi [9y^2]_{0}^{2}\) to obtain the internal volume of \(36\pi\text{ cm}^3\).
8Equate \(\int_{0}^{2} \pi \left(\frac{y}{a}\right) dy = 36\pi\) and solve backward to verify \(a = \frac{1}{18}\).
9The derivative representing the instantaneous rate at which colony area increases over time.
10The definite integral used to calculate the total bacterial colony area after \(5\text{ seconds}\).
Answer key: 1 B; 2 C; 3 1/18; 4 definite; 5 Understanding the problem; 6 Planning the strategy; 7 Implementing the strategy; 8 Check and reflect; 9 Rate of growth dA/dt; 10 Integral from 0 to 5 of (2t + 5) dt.

Keywords

Rate of growth (dA/dt) Volume of revolution (∫ πx² dy) Definite integral Four-step problem-solving model Depreciation rate (S'(t))