Linear Law and Non-Linear Relations

6.2 Linear Law and Non-Linear Relations
ADDITIONAL MATHEMATICS • Form 4 • Chapter 6: Linear Law

6.2 Linear Law and Non-Linear Relations

In scientific experiments and mathematical modelling, many relationships between two variables are non-linear, forming curves rather than straight lines. By applying linear law, most non-linear equations can be converted into the linear form \(Y = mX + c\). Converting non-linear relations into linear form allows a straight line of best fit to be drawn, making it significantly easier to find the values of unknown constants from the gradient and the vertical intercept.

Learning Objectives

  • Convert non-linear equations to the linear form \(Y = mX + c\).
  • Identify the variables representing \(Y\) and \(X\), the gradient \(m\), and the vertical intercept \(c\).
  • Plot straight line graphs of \(Y\) against \(X\) using given or suitable scales and draw the line of best fit.
  • Determine the values of unknown constants and find variable values using the gradient and vertical intercept from the plotted line of best fit.

Converting Non-Linear Equations into Linear Form \(Y = mX + c\)

A visual summary showing how polynomial, rational and exponential equations are algebraically manipulated and compared to \(Y = mX + c\).

Algebraic Manipulation Pathway

\(y = ax + \dfrac{b}{x} \xrightarrow{\times x} xy = ax^2 + b\)

Comparing with \(Y = mX + c\):

\(Y = xy,\quad X = x^2,\quad m = a,\quad c = b\)

Logarithmic Conversion Pathway

\(y = pq^x \xrightarrow{\log_{10}} \log_{10} y = (\log_{10} q)x + \log_{10} p\)

Comparing with \(Y = mX + c\):

\(Y = \log_{10} y,\quad X = x,\quad m = \log_{10} q,\quad c = \log_{10} p\)

Standard Linear Form

\(Y = mX + c\)

\(X\) and \(Y\) contain variables only; \(m\) and \(c\) contain constants only.

Short Explanation

Linear law provides an algebraic bridge to turn curves into straight lines.

1. Principle of Linear Law

Non-linear relations can be converted into linear relations of the form \(Y = mX + c\) so that a straight line can be drawn. It is easier to extract information, such as constants and rates, from a straight line graph than from a curve.

2. Smart Tips for Selecting \(X\), \(Y\), \(m\), and \(c\)

\(X\) and \(Y\) must contain variables only; they cannot contain unknown constants. \(m\) (the gradient) and \(c\) (the vertical intercept) must contain constants only; they cannot contain variables.

3. Rational and Polynomial Forms

For \(y = ax + \dfrac{b}{x}\), multiply both sides by \(x\) to get \(xy = ax^2 + b\), or divide both sides by \(x\) to get \(\dfrac{y}{x} = b\left(\dfrac{1}{x^2}\right) + a\).

4. Exponential Forms

For \(y = pq^x\), take \(\log_{10}\) of both sides: \(\log_{10} y = (\log_{10} q)x + \log_{10} p\). For \(y = \dfrac{p^x}{q}\), \(\log_{10} y = (\log_{10} p)x - \log_{10} q\).

Original Equation Conversion Method Linear Form \(Y = mX + c\)
\(y = ax + \dfrac{b}{x}\) Multiply both sides by \(x\) \(Y = xy,\ X = x^2,\ m = a,\ c = b\)
\(y = ax + \dfrac{b}{x}\) Divide both sides by \(x\) \(Y = \dfrac{y}{x},\ X = \dfrac{1}{x^2},\ m = b,\ c = a\)
\(3y - px^2 = qx\) Divide both sides by \(3x\) \(Y = \dfrac{y}{x},\ X = x,\ m = \dfrac{p}{3},\ c = \dfrac{q}{3}\)
\(y = pq^x\) Take \(\log_{10}\) of both sides \(Y = \log_{10} y,\ X = x,\ m = \log_{10} q,\ c = \log_{10} p\)
\(y = \dfrac{p^x}{q}\) Take \(\log_{10}\) of both sides \(Y = \log_{10} y,\ X = x,\ m = \log_{10} p,\ c = -\log_{10} q\)

Steps for Converting and Using Linear Law

1

If the equation involves powers of variables in polynomial or rational form, multiply or divide throughout by \(x\) or powers of \(x\).

2

If the equation involves index or exponential terms, apply logarithms to both sides and use the laws of logarithms.

3

Group the transformed equation into the structure \(Y = mX + c\). Ensure \(Y\) and \(X\) contain only variables, while \(m\) and \(c\) contain only constants.

4

After plotting \(Y\) against \(X\), read the intercept \(c\) and calculate the gradient \(m\). Substitute these into your algebraic expressions to solve for the constants.

Gradient of Line of Best Fit

\(m = \dfrac{Y_2 - Y_1}{X_2 - X_1}\)

Use two reference points on the line of best fit.

Logarithmic Laws Used

\(\log_{10}(ab) = \log_{10} a + \log_{10} b\)

\(\log_{10}\left(\dfrac{a}{b}\right) = \log_{10} a - \log_{10} b,\quad \log_{10}(a^b) = b \log_{10} a\)

Try to Answer First

Answer in your mind, then press "Check Answer".

1

Convert the non-linear equation \(y = px^2 - q\) into the linear form \(Y = mX + c\). State \(Y\), \(X\), \(m\), and \(c\).

2

Convert the equation \(y = ax^3 + bx^2\) into linear form such that the horizontal axis represents \(x\). State \(Y\), \(m\), and \(c\).

3

Given the non-linear equation \(y = \dfrac{p^x}{q}\), express it in linear form using base-10 logarithms. If the line of best fit of \(\log_{10} y\) against \(x\) has a vertical intercept of \(-2.5\), calculate the value of \(q\).

Common Mistakes

  • !Including constants in \(X\) or \(Y\): writing \(X = ax^2\) instead of \(X = x^2\). Variables \(X\) and \(Y\) must contain variables only.
  • !Including variables in \(m\) or \(c\): writing \(m = px\) instead of \(m = p\). The gradient \(m\) and intercept \(c\) must be pure constants.
  • !Neglecting negative signs in intercepts: when an equation results in \(Y = mX - \log_{10} q\), students often write \(c = \log_{10} q\) instead of \(c = -\log_{10} q\), leading to incorrect sign calculations for \(q\).
  • !Misapplying logarithmic laws: writing \(\log_{10}(pq^x) = x \log_{10}(pq)\) instead of \(\log_{10} p + x \log_{10} q\). The exponent \(x\) belongs only to \(q\), not to \(p\).
  • !Calculating gradient using original table values: using original coordinates \((x_1, y_1)\) instead of points on the line of best fit \((X_1, Y_1)\) from the transformed axes.

Concept Misunderstandings

Misunderstanding

There is only one unique way to convert any non-linear equation into linear form.

Correct Concept

An equation can often be converted in more than one way. For example, \(y = ax + \dfrac{b}{x}\) can be converted into \(xy = ax^2 + b\) or \(\dfrac{y}{x} = b\left(\dfrac{1}{x^2}\right) + a\).

Misunderstanding

Logarithms must be used for every non-linear conversion.

Correct Concept

Logarithms are necessary when the variable appears as an index/exponent, such as \(y = pq^x\), or when variables are related by power laws, such as \(y = ax^b\). Polynomial and rational relations are converted using basic algebraic operations like multiplying or dividing by powers of \(x\).

Summary

  • Linear law allows non-linear equations to be converted into the linear form \(Y = mX + c\).
  • Algebraic multiplication or division is used for rational and polynomial equations, while base-10 logarithms are applied when variables appear as exponents or powers.
  • \(X\) and \(Y\) must contain variables only; \(m\) and \(c\) must contain constants only.
  • By plotting \(Y\) against \(X\), drawing a straight line of best fit, and comparing the gradient \(m\) and intercept \(c\) with their algebraic equivalents, unknown constants and experimental values can be easily determined.

Short Activity

Objective: Convert non-linear equations into linear form and identify \(Y\), \(X\), \(m\), and \(c\).

A. Objective Quiz

1 Given the equation \(y = 5x^2 + 3x\), which of the following represents the equation in the linear form \(Y = mX + c\) when both sides are divided by \(x\)?

2 The variables \(x\) and \(y\) are related by the equation \(y = pq^x\). When converted into the linear form \(Y = mX + c\) using \(\log_{10}\), what are the gradient \(m\) and the vertical intercept \(c\)?

B. Fill in the Blanks

3 In the linear form \(Y = mX + c\), the variables \(X\) and \(Y\) must contain only variables, while \(m\) and \(c\) must contain only ________.

4 For the non-linear equation \(3y - px^2 = qx\), dividing both sides by \(3x\) yields the linear form \(\dfrac{y}{x} = \dfrac{p}{3}(x) + \dfrac{q}{3}\). If the vertical intercept of the line of best fit is 22, the value of \(q\) is ________.

C. Matching / Drag and Drop

Match each non-linear equation and its conversion method to its corresponding linear form \(Y = mX + c\). On a phone, tap a term first, then tap the matching box.

Non-Linear Equation and Method
\(y = ax + \dfrac{b}{x}\) (Multiply both sides by \(x\))
\(y = ax + \dfrac{b}{x}\) (Divide both sides by \(x\))
\(y = pq^x\) (Take \(\log_{10}\) on both sides)
\(y = \dfrac{p^x}{q}\) (Take \(\log_{10}\) on both sides)
\(y = ax^3 + bx^2\) (Divide both sides by \(x^2\))
\(y = hx^2 + x\) (Divide both sides by \(x\))
Linear Form Representation
5\(xy = a(x^2) + b\) where \(Y = xy\) and \(X = x^2\)
6\(\dfrac{y}{x} = b\left(\dfrac{1}{x^2}\right) + a\) where \(Y = \dfrac{y}{x}\) and \(X = \dfrac{1}{x^2}\)
7\(\log_{10} y = (\log_{10} q)x + \log_{10} p\) where \(Y = \log_{10} y\) and \(X = x\)
8\(\log_{10} y = (\log_{10} p)x - \log_{10} q\) where \(m = \log_{10} p\) and \(c = -\log_{10} q\)
9\(\dfrac{y}{x^2} = ax + b\) where \(Y = \dfrac{y}{x^2}\) and \(X = x\)
10\(\dfrac{y}{x} = hx + 1\) where \(Y = \dfrac{y}{x}\) and \(X = x\)
Answer key: 1 A; 2 C; 3 constants; 4 66; 5 \(xy = a(x^2) + b\); 6 \(\dfrac{y}{x} = b\left(\dfrac{1}{x^2}\right) + a\); 7 \(\log_{10} y = (\log_{10} q)x + \log_{10} p\); 8 \(\log_{10} y = (\log_{10} p)x - \log_{10} q\); 9 \(\dfrac{y}{x^2} = ax + b\); 10 \(\dfrac{y}{x} = hx + 1\).

Keywords

Linear Law Linear Form Line of Best Fit Gradient Vertical Intercept Logarithmic Form

Linear Law and Non-Linear Relations

6.2 Linear Law and Non-Linear Relations
ADDITIONAL MATHEMATICS • Form 4 • Chapter 6: Linear Law

6.2 Linear Law and Non-Linear Relations

In scientific experiments and mathematical modelling, many relationships between two variables are non-linear, forming curves rather than straight lines. By applying linear law, most non-linear equations can be converted into the linear form \(Y = mX + c\). Converting non-linear relations into linear form allows a straight line of best fit to be drawn, making it significantly easier to find the values of unknown constants from the gradient and the vertical intercept.

Learning Objectives

  • Convert non-linear equations to the linear form \(Y = mX + c\).
  • Identify the variables representing \(Y\) and \(X\), the gradient \(m\), and the vertical intercept \(c\).
  • Plot straight line graphs of \(Y\) against \(X\) using given or suitable scales and draw the line of best fit.
  • Determine the values of unknown constants and find variable values using the gradient and vertical intercept from the plotted line of best fit.

Converting Non-Linear Equations into Linear Form \(Y = mX + c\)

A visual summary showing how polynomial, rational and exponential equations are algebraically manipulated and compared to \(Y = mX + c\).

Algebraic Manipulation Pathway

\(y = ax + \dfrac{b}{x} \xrightarrow{\times x} xy = ax^2 + b\)

Comparing with \(Y = mX + c\):

\(Y = xy,\quad X = x^2,\quad m = a,\quad c = b\)

Logarithmic Conversion Pathway

\(y = pq^x \xrightarrow{\log_{10}} \log_{10} y = (\log_{10} q)x + \log_{10} p\)

Comparing with \(Y = mX + c\):

\(Y = \log_{10} y,\quad X = x,\quad m = \log_{10} q,\quad c = \log_{10} p\)

Standard Linear Form

\(Y = mX + c\)

\(X\) and \(Y\) contain variables only; \(m\) and \(c\) contain constants only.

Short Explanation

Linear law provides an algebraic bridge to turn curves into straight lines.

1. Principle of Linear Law

Non-linear relations can be converted into linear relations of the form \(Y = mX + c\) so that a straight line can be drawn. It is easier to extract information, such as constants and rates, from a straight line graph than from a curve.

2. Smart Tips for Selecting \(X\), \(Y\), \(m\), and \(c\)

\(X\) and \(Y\) must contain variables only; they cannot contain unknown constants. \(m\) (the gradient) and \(c\) (the vertical intercept) must contain constants only; they cannot contain variables.

3. Rational and Polynomial Forms

For \(y = ax + \dfrac{b}{x}\), multiply both sides by \(x\) to get \(xy = ax^2 + b\), or divide both sides by \(x\) to get \(\dfrac{y}{x} = b\left(\dfrac{1}{x^2}\right) + a\).

4. Exponential Forms

For \(y = pq^x\), take \(\log_{10}\) of both sides: \(\log_{10} y = (\log_{10} q)x + \log_{10} p\). For \(y = \dfrac{p^x}{q}\), \(\log_{10} y = (\log_{10} p)x - \log_{10} q\).

Original Equation Conversion Method Linear Form \(Y = mX + c\)
\(y = ax + \dfrac{b}{x}\) Multiply both sides by \(x\) \(Y = xy,\ X = x^2,\ m = a,\ c = b\)
\(y = ax + \dfrac{b}{x}\) Divide both sides by \(x\) \(Y = \dfrac{y}{x},\ X = \dfrac{1}{x^2},\ m = b,\ c = a\)
\(3y - px^2 = qx\) Divide both sides by \(3x\) \(Y = \dfrac{y}{x},\ X = x,\ m = \dfrac{p}{3},\ c = \dfrac{q}{3}\)
\(y = pq^x\) Take \(\log_{10}\) of both sides \(Y = \log_{10} y,\ X = x,\ m = \log_{10} q,\ c = \log_{10} p\)
\(y = \dfrac{p^x}{q}\) Take \(\log_{10}\) of both sides \(Y = \log_{10} y,\ X = x,\ m = \log_{10} p,\ c = -\log_{10} q\)

Steps for Converting and Using Linear Law

1

If the equation involves powers of variables in polynomial or rational form, multiply or divide throughout by \(x\) or powers of \(x\).

2

If the equation involves index or exponential terms, apply logarithms to both sides and use the laws of logarithms.

3

Group the transformed equation into the structure \(Y = mX + c\). Ensure \(Y\) and \(X\) contain only variables, while \(m\) and \(c\) contain only constants.

4

After plotting \(Y\) against \(X\), read the intercept \(c\) and calculate the gradient \(m\). Substitute these into your algebraic expressions to solve for the constants.

Gradient of Line of Best Fit

\(m = \dfrac{Y_2 - Y_1}{X_2 - X_1}\)

Use two reference points on the line of best fit.

Logarithmic Laws Used

\(\log_{10}(ab) = \log_{10} a + \log_{10} b\)

\(\log_{10}\left(\dfrac{a}{b}\right) = \log_{10} a - \log_{10} b,\quad \log_{10}(a^b) = b \log_{10} a\)

Try to Answer First

Answer in your mind, then press "Check Answer".

1

Convert the non-linear equation \(y = px^2 - q\) into the linear form \(Y = mX + c\). State \(Y\), \(X\), \(m\), and \(c\).

2

Convert the equation \(y = ax^3 + bx^2\) into linear form such that the horizontal axis represents \(x\). State \(Y\), \(m\), and \(c\).

3

Given the non-linear equation \(y = \dfrac{p^x}{q}\), express it in linear form using base-10 logarithms. If the line of best fit of \(\log_{10} y\) against \(x\) has a vertical intercept of \(-2.5\), calculate the value of \(q\).

Common Mistakes

  • !Including constants in \(X\) or \(Y\): writing \(X = ax^2\) instead of \(X = x^2\). Variables \(X\) and \(Y\) must contain variables only.
  • !Including variables in \(m\) or \(c\): writing \(m = px\) instead of \(m = p\). The gradient \(m\) and intercept \(c\) must be pure constants.
  • !Neglecting negative signs in intercepts: when an equation results in \(Y = mX - \log_{10} q\), students often write \(c = \log_{10} q\) instead of \(c = -\log_{10} q\), leading to incorrect sign calculations for \(q\).
  • !Misapplying logarithmic laws: writing \(\log_{10}(pq^x) = x \log_{10}(pq)\) instead of \(\log_{10} p + x \log_{10} q\). The exponent \(x\) belongs only to \(q\), not to \(p\).
  • !Calculating gradient using original table values: using original coordinates \((x_1, y_1)\) instead of points on the line of best fit \((X_1, Y_1)\) from the transformed axes.

Concept Misunderstandings

Misunderstanding

There is only one unique way to convert any non-linear equation into linear form.

Correct Concept

An equation can often be converted in more than one way. For example, \(y = ax + \dfrac{b}{x}\) can be converted into \(xy = ax^2 + b\) or \(\dfrac{y}{x} = b\left(\dfrac{1}{x^2}\right) + a\).

Misunderstanding

Logarithms must be used for every non-linear conversion.

Correct Concept

Logarithms are necessary when the variable appears as an index/exponent, such as \(y = pq^x\), or when variables are related by power laws, such as \(y = ax^b\). Polynomial and rational relations are converted using basic algebraic operations like multiplying or dividing by powers of \(x\).

Summary

  • Linear law allows non-linear equations to be converted into the linear form \(Y = mX + c\).
  • Algebraic multiplication or division is used for rational and polynomial equations, while base-10 logarithms are applied when variables appear as exponents or powers.
  • \(X\) and \(Y\) must contain variables only; \(m\) and \(c\) must contain constants only.
  • By plotting \(Y\) against \(X\), drawing a straight line of best fit, and comparing the gradient \(m\) and intercept \(c\) with their algebraic equivalents, unknown constants and experimental values can be easily determined.

Short Activity

Objective: Convert non-linear equations into linear form and identify \(Y\), \(X\), \(m\), and \(c\).

A. Objective Quiz

1 Given the equation \(y = 5x^2 + 3x\), which of the following represents the equation in the linear form \(Y = mX + c\) when both sides are divided by \(x\)?

2 The variables \(x\) and \(y\) are related by the equation \(y = pq^x\). When converted into the linear form \(Y = mX + c\) using \(\log_{10}\), what are the gradient \(m\) and the vertical intercept \(c\)?

B. Fill in the Blanks

3 In the linear form \(Y = mX + c\), the variables \(X\) and \(Y\) must contain only variables, while \(m\) and \(c\) must contain only ________.

4 For the non-linear equation \(3y - px^2 = qx\), dividing both sides by \(3x\) yields the linear form \(\dfrac{y}{x} = \dfrac{p}{3}(x) + \dfrac{q}{3}\). If the vertical intercept of the line of best fit is 22, the value of \(q\) is ________.

C. Matching / Drag and Drop

Match each non-linear equation and its conversion method to its corresponding linear form \(Y = mX + c\). On a phone, tap a term first, then tap the matching box.

Non-Linear Equation and Method
\(y = ax + \dfrac{b}{x}\) (Multiply both sides by \(x\))
\(y = ax + \dfrac{b}{x}\) (Divide both sides by \(x\))
\(y = pq^x\) (Take \(\log_{10}\) on both sides)
\(y = \dfrac{p^x}{q}\) (Take \(\log_{10}\) on both sides)
\(y = ax^3 + bx^2\) (Divide both sides by \(x^2\))
\(y = hx^2 + x\) (Divide both sides by \(x\))
Linear Form Representation
5\(xy = a(x^2) + b\) where \(Y = xy\) and \(X = x^2\)
6\(\dfrac{y}{x} = b\left(\dfrac{1}{x^2}\right) + a\) where \(Y = \dfrac{y}{x}\) and \(X = \dfrac{1}{x^2}\)
7\(\log_{10} y = (\log_{10} q)x + \log_{10} p\) where \(Y = \log_{10} y\) and \(X = x\)
8\(\log_{10} y = (\log_{10} p)x - \log_{10} q\) where \(m = \log_{10} p\) and \(c = -\log_{10} q\)
9\(\dfrac{y}{x^2} = ax + b\) where \(Y = \dfrac{y}{x^2}\) and \(X = x\)
10\(\dfrac{y}{x} = hx + 1\) where \(Y = \dfrac{y}{x}\) and \(X = x\)
Answer key: 1 A; 2 C; 3 constants; 4 66; 5 \(xy = a(x^2) + b\); 6 \(\dfrac{y}{x} = b\left(\dfrac{1}{x^2}\right) + a\); 7 \(\log_{10} y = (\log_{10} q)x + \log_{10} p\); 8 \(\log_{10} y = (\log_{10} p)x - \log_{10} q\); 9 \(\dfrac{y}{x^2} = ax + b\); 10 \(\dfrac{y}{x} = hx + 1\).

Keywords

Linear Law Linear Form Line of Best Fit Gradient Vertical Intercept Logarithmic Form