Arithmetic Progressions

5.1 Arithmetic Progressions
ADDITIONAL MATHEMATICS • Form 4 • Chapter 5: Progressions

5.1 Arithmetic Progressions

An arithmetic progression (AP) is a sequence of numbers in which each term after the first is obtained by adding a constant value to the preceding term. This constant difference between consecutive terms is known as the common difference, denoted by \(d\). Arithmetic progressions are widely applied in modeling uniform additions or deductions, such as layered building steps, seating capacities across auditorium rows, uniform salary increments, or daily work production.

Learning Objectives

  • Identify arithmetic progressions and determine their common differences.
  • Derive and use the formula for the \(n^{\text{th}}\) term, \(T_n = a + (n - 1)d\).
  • Derive and use the formula for the sum of the first \(n\) terms, \(S_n = \dfrac{n}{2}[2a + (n - 1)d]\) and \(S_n = \dfrac{n}{2}[a + l]\).
  • Find the \(n^{\text{th}}\) term using the relationship \(T_n = S_n - S_{n-1}\).
  • Solve daily real-world problems involving arithmetic progressions.

Geometric Derivation of the Sum of an Arithmetic Series (\(S_n\))

Illustrate why \(S_n = \dfrac{n}{2}[2a + (n - 1)d]\) by combining two staircase-shaped stair-step bar diagrams to form a single solid rectangle.

Geometric derivation of the sum of an arithmetic series showing two staircase-shaped bar diagrams combined to form a rectangle of width n and height 2a plus n minus 1 times d

Short Explanation

An arithmetic progression represents steady, linear change. The key characteristics are the first term \(a\) and the uniform common difference \(d\).

1. Identifying Arithmetic Progressions and the Common Difference (\(d\))

A sequence is a set of numbers arranged according to a specific pattern. Each number in a sequence is called a term, written as \(T_1, T_2, T_3, \ldots, T_n\). A finite sequence has a limited number of terms, while an infinite sequence continues indefinitely. An arithmetic progression is a sequence where each subsequent term is obtained by adding a fixed constant to the preceding term. The common difference is \(d = T_2 - T_1 = T_3 - T_2 = \ldots = T_n - T_{n-1}\). Note: \(d \neq T_1 - T_2 \neq T_2 - T_3 \neq \ldots \neq T_{n-1} - T_n\). The subtraction must always be a succeeding term minus the preceding term.

2. Deriving the Formula of the \(n^{\text{th}}\) Term (\(T_n\))

Let the first term be \(a\) (\(T_1 = a\)) and the common difference be \(d\). Then \(T_1 = a = a + 0d\), \(T_2 = a + d = a + 1d\), \(T_3 = (a + d) + d = a + 2d\). By deduction, the formula for the \(n^{\text{th}}\) term is \(T_n = a + (n - 1)d\), where \(a\) is the first term, \(d\) is the common difference, and \(n\) is the number of terms (\(n \in \mathbb{Z}^+\)).

3. Deriving the Formula for the Sum of the First \(n\) Terms (\(S_n\))

An arithmetic series is \(T_1 + T_2 + T_3 + \ldots + T_n\). By representing terms as grid heights and combining two identical sets of grids, a uniform rectangle of width \(n\) and height \([2a + (n - 1)d]\) is formed. Since \(S_n\) represents half of this combined area: \(S_n = \dfrac{n}{2}[2a + (n - 1)d]\). Using the last term \(l = T_n = a + (n - 1)d\), the sum can also be written as \(S_n = \dfrac{n}{2}[a + T_n]\) or \(S_n = \dfrac{n}{2}[a + l]\).

4. Relationship Between \(T_n\) and \(S_n\)

The \(n^{\text{th}}\) term can be found by subtracting the sum of the first \((n - 1)\) terms from the sum of the first \(n\) terms: \(T_n = S_n - S_{n-1}\). Similarly, the sum of a specific block of consecutive terms can be evaluated using sums from the start. For example, \(S_8 - S_5 = T_6 + T_7 + T_8\), and the sum of 200 terms after the first 50 terms is given by \(S_{250} - S_{50}\).

Concept Formula / Expression Meaning
Common difference \(d = T_n - T_{n-1}\) Constant difference between consecutive terms.
\(n^{\text{th}}\) term \(T_n = a + (n - 1)d\) Term located at position \(n\).
Sum of first \(n\) terms \(S_n = \dfrac{n}{2}[2a + (n - 1)d]\) Total of the first \(n\) terms.
Sum using last term \(S_n = \dfrac{n}{2}[a + l]\) Alternative sum formula using the last term \(l\).
Term from sums \(T_n = S_n - S_{n-1}\) Recover an individual term from sum formulas.

Steps for Solving Problems Involving Arithmetic Progressions

1

Understanding the problem: Identify the given values (\(a\), \(d\), \(T_n\), or \(S_n\)) and what needs to be determined.

2

Planning a strategy: Formulate the arithmetic progression and choose the appropriate formula (\(T_n\) or \(S_n\)).

3

Implementing the strategy: Solve algebraically or solve quadratic inequalities where \(n\) must be a positive integer (\(n \in \mathbb{Z}^+\)).

4

Making a conclusion: State the final result in the context of the question.

\(n^{\text{th}}\) term of an arithmetic progression

\(T_n = a + (n - 1)d\)

Use this to find any term directly without listing every preceding number.

Sum of the first \(n\) terms

\(S_n = \dfrac{n}{2}[2a + (n - 1)d]\)

Pairing the first and last terms yields identical sums.

Try to Answer First

Answer in your mind, then press "Check Answer".

1

Determine whether the sequence \(5 - x, 5, 5 + x, \ldots\) is an arithmetic progression and state its common difference.

2

Find the \(15^{\text{th}}\) term of the arithmetic progression \(-4, 2, 8, \ldots\).

3

The sum of the first \(n\) terms of an arithmetic progression is given by \(S_n = 2n^2 - 5n\). Find the first term, \(T_1\), and the \(9^{\text{th}}\) term, \(T_9\).

Common Mistakes

  • !Subtracting terms in reverse order when finding the common difference, for example writing \(d = T_1 - T_2\) instead of \(d = T_2 - T_1\).
  • !Forgetting to use brackets when subtracting negative terms, for example computing \(2 - -4\) as \(2 - 4 = -2\) instead of \(2 - (-4) = 6\).
  • !Using \((n)\) instead of \((n - 1)\) in the formula for \(T_n\), leading to \(a + nd\).
  • !Confusing the \(n^{\text{th}}\) term (\(T_n\)) with the sum of the first \(n\) terms (\(S_n\)).
  • !Selecting a negative or non-integer solution for the number of terms \(n\) when solving quadratic equations or inequalities. The number of terms \(n\) must be a positive integer, \(n \in \mathbb{Z}^+\).

Concept Misunderstandings

Misunderstanding

Assuming that a sequence is an arithmetic progression just because the first two terms have a difference, without checking subsequent pairs.

Correct Concept

You must verify that the difference between consecutive pairs is equal, for example checking \(T_2 - T_1\) and \(T_3 - T_2\).

Misunderstanding

Believing that the common difference \(d\) must always be positive.

Correct Concept

\(d\) can be negative for decreasing sequences, zero for constant sequences, or a fraction.

Misunderstanding

Thinking that \(T_n\) equals \(\dfrac{S_n}{n}\).

Correct Concept

The correct relationship between terms and sums is \(T_n = S_n - S_{n-1}\).

Misunderstanding

Mistakenly assuming that finding the sum from term \(p\) to term \(q\) is \(S_q - S_p\).

Correct Concept

The correct expression is \(S_q - S_{p-1}\).

Summary

  • An arithmetic progression is characterised by a constant common difference \(d = T_n - T_{n-1}\).
  • The general \(n^{\text{th}}\) term is given by \(T_n = a + (n - 1)d\).
  • The sum of the first \(n\) terms is given by \(S_n = \dfrac{n}{2}[2a + (n - 1)d] = \dfrac{n}{2}[a + l]\).
  • Any term can be obtained from the sum series using \(T_n = S_n - S_{n-1}\).

Short Activity

Objective: Identify arithmetic progressions, use the \(n^{\text{th}}\) term and sum formulas, and match key concepts.

A. Objective Quiz

1 What is the common difference, \(d\), of the arithmetic progression \(-35, -21, -7, \ldots\)?

2 Given an arithmetic progression with first term \(a = 10\) and common difference \(d = -4\), what is the value of the \(7^{\text{th}}\) term, \(T_7\)?

B. Fill in the Blanks

3 In general, the \(n^{\text{th}}\) term of an arithmetic progression can be derived from the sum of its terms using the formula \(T_n = S_n - \) ________.

4 When the first term is \(a\) and the last term is \(l\), the sum of the first \(n\) terms can be written as \(S_n = \dfrac{n}{2}[\) ________ \(]\).

C. Matching / Drag and Drop

Match each arithmetic progression concept or problem statement with its correct mathematical expression or value. On a phone, tap a term first, then tap the matching box.

Concept / Problem
Formula for the common difference
\(n^{\text{th}}\) term formula
Sum of the first \(n\) terms formula
Expression for \(T_6 + T_7 + T_8\)
Common difference of \(T_n = 8 - 3n\)
\(4^{\text{th}}\) term when \(T_n = 8 - 5n\)
Correct Value / Expression
5\(T_n - T_{n-1}\)
6\(a + (n - 1)d\)
7\(\dfrac{n}{2}[2a + (n - 1)d]\)
8\(S_8 - S_5\)
9\(-3\)
10\(-12\)
Answer key: 1 B; 2 B; 3 S_{n-1}; 4 a + l; 5 \(T_n - T_{n-1}\); 6 \(a + (n - 1)d\); 7 \(\dfrac{n}{2}[2a + (n - 1)d]\); 8 \(S_8 - S_5\); 9 \(-3\); 10 \(-12\).

Keywords

Arithmetic Progression Common Difference First Term nth Term Arithmetic Series Sum of the First n Terms Last Term

Arithmetic Progressions

5.1 Arithmetic Progressions
ADDITIONAL MATHEMATICS • Form 4 • Chapter 5: Progressions

5.1 Arithmetic Progressions

An arithmetic progression (AP) is a sequence of numbers in which each term after the first is obtained by adding a constant value to the preceding term. This constant difference between consecutive terms is known as the common difference, denoted by \(d\). Arithmetic progressions are widely applied in modeling uniform additions or deductions, such as layered building steps, seating capacities across auditorium rows, uniform salary increments, or daily work production.

Learning Objectives

  • Identify arithmetic progressions and determine their common differences.
  • Derive and use the formula for the \(n^{\text{th}}\) term, \(T_n = a + (n - 1)d\).
  • Derive and use the formula for the sum of the first \(n\) terms, \(S_n = \dfrac{n}{2}[2a + (n - 1)d]\) and \(S_n = \dfrac{n}{2}[a + l]\).
  • Find the \(n^{\text{th}}\) term using the relationship \(T_n = S_n - S_{n-1}\).
  • Solve daily real-world problems involving arithmetic progressions.

Geometric Derivation of the Sum of an Arithmetic Series (\(S_n\))

Illustrate why \(S_n = \dfrac{n}{2}[2a + (n - 1)d]\) by combining two staircase-shaped stair-step bar diagrams to form a single solid rectangle.

Geometric derivation of the sum of an arithmetic series showing two staircase-shaped bar diagrams combined to form a rectangle of width n and height 2a plus n minus 1 times d

Short Explanation

An arithmetic progression represents steady, linear change. The key characteristics are the first term \(a\) and the uniform common difference \(d\).

1. Identifying Arithmetic Progressions and the Common Difference (\(d\))

A sequence is a set of numbers arranged according to a specific pattern. Each number in a sequence is called a term, written as \(T_1, T_2, T_3, \ldots, T_n\). A finite sequence has a limited number of terms, while an infinite sequence continues indefinitely. An arithmetic progression is a sequence where each subsequent term is obtained by adding a fixed constant to the preceding term. The common difference is \(d = T_2 - T_1 = T_3 - T_2 = \ldots = T_n - T_{n-1}\). Note: \(d \neq T_1 - T_2 \neq T_2 - T_3 \neq \ldots \neq T_{n-1} - T_n\). The subtraction must always be a succeeding term minus the preceding term.

2. Deriving the Formula of the \(n^{\text{th}}\) Term (\(T_n\))

Let the first term be \(a\) (\(T_1 = a\)) and the common difference be \(d\). Then \(T_1 = a = a + 0d\), \(T_2 = a + d = a + 1d\), \(T_3 = (a + d) + d = a + 2d\). By deduction, the formula for the \(n^{\text{th}}\) term is \(T_n = a + (n - 1)d\), where \(a\) is the first term, \(d\) is the common difference, and \(n\) is the number of terms (\(n \in \mathbb{Z}^+\)).

3. Deriving the Formula for the Sum of the First \(n\) Terms (\(S_n\))

An arithmetic series is \(T_1 + T_2 + T_3 + \ldots + T_n\). By representing terms as grid heights and combining two identical sets of grids, a uniform rectangle of width \(n\) and height \([2a + (n - 1)d]\) is formed. Since \(S_n\) represents half of this combined area: \(S_n = \dfrac{n}{2}[2a + (n - 1)d]\). Using the last term \(l = T_n = a + (n - 1)d\), the sum can also be written as \(S_n = \dfrac{n}{2}[a + T_n]\) or \(S_n = \dfrac{n}{2}[a + l]\).

4. Relationship Between \(T_n\) and \(S_n\)

The \(n^{\text{th}}\) term can be found by subtracting the sum of the first \((n - 1)\) terms from the sum of the first \(n\) terms: \(T_n = S_n - S_{n-1}\). Similarly, the sum of a specific block of consecutive terms can be evaluated using sums from the start. For example, \(S_8 - S_5 = T_6 + T_7 + T_8\), and the sum of 200 terms after the first 50 terms is given by \(S_{250} - S_{50}\).

Concept Formula / Expression Meaning
Common difference \(d = T_n - T_{n-1}\) Constant difference between consecutive terms.
\(n^{\text{th}}\) term \(T_n = a + (n - 1)d\) Term located at position \(n\).
Sum of first \(n\) terms \(S_n = \dfrac{n}{2}[2a + (n - 1)d]\) Total of the first \(n\) terms.
Sum using last term \(S_n = \dfrac{n}{2}[a + l]\) Alternative sum formula using the last term \(l\).
Term from sums \(T_n = S_n - S_{n-1}\) Recover an individual term from sum formulas.

Steps for Solving Problems Involving Arithmetic Progressions

1

Understanding the problem: Identify the given values (\(a\), \(d\), \(T_n\), or \(S_n\)) and what needs to be determined.

2

Planning a strategy: Formulate the arithmetic progression and choose the appropriate formula (\(T_n\) or \(S_n\)).

3

Implementing the strategy: Solve algebraically or solve quadratic inequalities where \(n\) must be a positive integer (\(n \in \mathbb{Z}^+\)).

4

Making a conclusion: State the final result in the context of the question.

\(n^{\text{th}}\) term of an arithmetic progression

\(T_n = a + (n - 1)d\)

Use this to find any term directly without listing every preceding number.

Sum of the first \(n\) terms

\(S_n = \dfrac{n}{2}[2a + (n - 1)d]\)

Pairing the first and last terms yields identical sums.

Try to Answer First

Answer in your mind, then press "Check Answer".

1

Determine whether the sequence \(5 - x, 5, 5 + x, \ldots\) is an arithmetic progression and state its common difference.

2

Find the \(15^{\text{th}}\) term of the arithmetic progression \(-4, 2, 8, \ldots\).

3

The sum of the first \(n\) terms of an arithmetic progression is given by \(S_n = 2n^2 - 5n\). Find the first term, \(T_1\), and the \(9^{\text{th}}\) term, \(T_9\).

Common Mistakes

  • !Subtracting terms in reverse order when finding the common difference, for example writing \(d = T_1 - T_2\) instead of \(d = T_2 - T_1\).
  • !Forgetting to use brackets when subtracting negative terms, for example computing \(2 - -4\) as \(2 - 4 = -2\) instead of \(2 - (-4) = 6\).
  • !Using \((n)\) instead of \((n - 1)\) in the formula for \(T_n\), leading to \(a + nd\).
  • !Confusing the \(n^{\text{th}}\) term (\(T_n\)) with the sum of the first \(n\) terms (\(S_n\)).
  • !Selecting a negative or non-integer solution for the number of terms \(n\) when solving quadratic equations or inequalities. The number of terms \(n\) must be a positive integer, \(n \in \mathbb{Z}^+\).

Concept Misunderstandings

Misunderstanding

Assuming that a sequence is an arithmetic progression just because the first two terms have a difference, without checking subsequent pairs.

Correct Concept

You must verify that the difference between consecutive pairs is equal, for example checking \(T_2 - T_1\) and \(T_3 - T_2\).

Misunderstanding

Believing that the common difference \(d\) must always be positive.

Correct Concept

\(d\) can be negative for decreasing sequences, zero for constant sequences, or a fraction.

Misunderstanding

Thinking that \(T_n\) equals \(\dfrac{S_n}{n}\).

Correct Concept

The correct relationship between terms and sums is \(T_n = S_n - S_{n-1}\).

Misunderstanding

Mistakenly assuming that finding the sum from term \(p\) to term \(q\) is \(S_q - S_p\).

Correct Concept

The correct expression is \(S_q - S_{p-1}\).

Summary

  • An arithmetic progression is characterised by a constant common difference \(d = T_n - T_{n-1}\).
  • The general \(n^{\text{th}}\) term is given by \(T_n = a + (n - 1)d\).
  • The sum of the first \(n\) terms is given by \(S_n = \dfrac{n}{2}[2a + (n - 1)d] = \dfrac{n}{2}[a + l]\).
  • Any term can be obtained from the sum series using \(T_n = S_n - S_{n-1}\).

Short Activity

Objective: Identify arithmetic progressions, use the \(n^{\text{th}}\) term and sum formulas, and match key concepts.

A. Objective Quiz

1 What is the common difference, \(d\), of the arithmetic progression \(-35, -21, -7, \ldots\)?

2 Given an arithmetic progression with first term \(a = 10\) and common difference \(d = -4\), what is the value of the \(7^{\text{th}}\) term, \(T_7\)?

B. Fill in the Blanks

3 In general, the \(n^{\text{th}}\) term of an arithmetic progression can be derived from the sum of its terms using the formula \(T_n = S_n - \) ________.

4 When the first term is \(a\) and the last term is \(l\), the sum of the first \(n\) terms can be written as \(S_n = \dfrac{n}{2}[\) ________ \(]\).

C. Matching / Drag and Drop

Match each arithmetic progression concept or problem statement with its correct mathematical expression or value. On a phone, tap a term first, then tap the matching box.

Concept / Problem
Formula for the common difference
\(n^{\text{th}}\) term formula
Sum of the first \(n\) terms formula
Expression for \(T_6 + T_7 + T_8\)
Common difference of \(T_n = 8 - 3n\)
\(4^{\text{th}}\) term when \(T_n = 8 - 5n\)
Correct Value / Expression
5\(T_n - T_{n-1}\)
6\(a + (n - 1)d\)
7\(\dfrac{n}{2}[2a + (n - 1)d]\)
8\(S_8 - S_5\)
9\(-3\)
10\(-12\)
Answer key: 1 B; 2 B; 3 S_{n-1}; 4 a + l; 5 \(T_n - T_{n-1}\); 6 \(a + (n - 1)d\); 7 \(\dfrac{n}{2}[2a + (n - 1)d]\); 8 \(S_8 - S_5\); 9 \(-3\); 10 \(-12\).

Keywords

Arithmetic Progression Common Difference First Term nth Term Arithmetic Series Sum of the First n Terms Last Term