Voltaic Cell (6)

The half reduction equations for the arrangement of the voltaic cell for the pair of argentum, Ag and ferrum, Fe

Half reduction equation : Ag+ + e− → Ag

The overall ionic equation for the arrangement of the voltaic cell for the pair of argentum, Ag and ferrum, Fe

Overall ionic equation : Fe + 2Ag+ → Fe2+ + 2Ag

The voltage of the cell for the arrangement of the voltaic cell for the pair of argentum, Ag and ferum, Fe

Eº cell = (+0.80) – (-0.44) = +1.24 V

The voltage of the cell: Ni(s) | Ni2+(aq) || Pb2+(aq) | Pb(s)

Eº cell = (+0.13) – (-0.25) = + 0.12 V

The voltage of the cell: Pt(s) | I−(aq), I2 (aq) || Ag+(aq) | Ag(s)

Eºcell = (+0.80) – (+0.54) = + 0.26 V

The voltage of the cell Pt(s) | Fe2+(aq), Fe3+(aq) || Ag+(aq) | Ag(s)

Eºcell = (+0.80) – (+0.77) = + 0.03 V

The voltage for the cell Pt(s) | Br− (aq), Br2 (aq) || Cl2 (aq), Cl−(aq) | Pt(s)

Eºcell = (+1.36) – (+1.07) = + 0.29 V