Voltaic Cell (4)

Chemistry

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A Daniell cell (1)

In a Daniell cell: the E° for two half-cells are: - Zn2+(aq) + 2e− ⇌ Zn(s) E0 = - 0.76 V - Cu2+(aq) + 2e− ⇌ Cu(s) E0 = + 0.34 V

A Daniell cell (2)

In a Daniell cell: t, zinc, Zn with a more negative E0 value is the negative terminal (anode)

A Daniell cell (3)

In a Daniell cell, copper, Cu with a more positive E° value is the positive terminal (cathode).

A Daniell cell (4)

In a Daniell cell, zinc electrode (anode) undergo oxidation reaction: Zn(s) → Zn2+(aq) + 2e−

A Daniell cell (5)

In a Daniell cell, copper electrode (cathode) undergo reduction reaction: Cu2+(aq) + 2e− → Cu

A Daniell cell (6)

Overall ionic equation for Danial Cell is: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)

A Danial Cell (7)

Electrons flow from zinc electrode, Zn to copper electrode, Cu through a connecting wire

Way to write the voltaic cell (1)

- The voltaic cell can be written in the form of cell notation

Way to write the voltaic cell (2)

Anode is written on the left side of the cell notation and cathode on the right side

Cell notation for a Daniell cell

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