Ionic Bond (2)

Chemistry

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Ionic Bond (2)

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Example of formation of sodium ion, Na+ (cation) (1)

To achieve a stable electron arrangement, sodium atom, Na needs to donate an electron

Example of formation of sodium ion, Na+ (cation) (2)

The process of donating an electron from the valence shell of sodium atom, Na is much easier compared to accepting seven electrons from another atom

Example of formation of sodium ion, Na+ (cation) (3)

After donating its valence electron, sodium ion, Na+ achieves a stable octet electron arrangement

Example of formation of sodium ion, Na+ (cation) (4)

Sodium ion, Na+ has 11 protons and 10 electrons, thus the charge for a sodium ion, Na+ is +1

Example of formation of sodium ion, Na+ (cation) (5)

Half-equation for the formation of sodium ion, Na+: Na → Na+ + e–

Example of formation of fluoride ion, F– (anion) (1)

To achieve a stable electron arrangement, fluorine atom, F will accept an electron

Example of formation of fluoride ion, F- (anion) (2)

The process of accepting one electron to the valence shell of fluorine atom, F is easier compared to donating its seven valence electrons to another atom

Example of formation of fluoride ion, F– (anion) (3)

After receiving one valence electron, fluoride ion, F– achieves a stable octet electron arrangement

Example of formation of fluoride ion, F- (anion) (4)

Fluoride ion, F– has 9 protons and 10 electrons, so the charge of fluoride ion, F– is –1

Example of formation of fluoride ion, F– (anion) (5)

Half-equation for the formation of fluoride ion, F–: F + e– → F–

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