1.3 |
Area of Sector of a Circle |
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Type of Sector |
If a circle is divided into two sectors of different sizes, the smaller sector is known as the minor sector while the larger sector is known as the major sector. |
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Formula for Area of a Sector |

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Based on the diagram above, area of sector can be write as:
\(\text{Area}=\dfrac{1}{2}r^2\theta\)
where \(r\) is the radius and \(\theta\) is the angle in radians.
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Another formula to calculate the area of a sector is given by:
\(\text{Area}=\dfrac{\theta}{360^\circ}\times\pi r^2\)
where \(r\) is the radius and \(\theta\) is the angle in degrees.
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Area of a Segment |

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Formula for Area of Segment |
Based on figure above, area of segment can be calculate by:
\(= \text{Area of the sector } OPRQ - \text{Area of the isosceles }\triangle{OPQ} \ \)
or can be calculated by using formula:

where \(r\) is the radius of the sector and \(\theta\) is the angle of the sector.
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Example \(1\) |

Based on the diagram above, find the area of sector \(AOB\).
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Based on the figure, given,
\(r=9\) cm,
\(\theta=1.3\text{ rad}\).
Area of sector \(AOB\):
\(\begin{aligned} &=\dfrac{1}{2}r^2 \theta \\\\ &=\dfrac{1}{2}(9)^2(1.3) \\\\ &= 52.65 \text{ cm}^2. \end{aligned}\)
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Example \(2\) |

Diagram above shows a sector of a circle, with centre \(O\) and a radius of \(7\) cm.
The length of the arc \(AB\) is \(5\) cm.
Find the area of the shaded region.
[ Use \(\pi=3.142\) ]
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Find the value of \(\theta\) by using arc length formula,
\(\begin{aligned} s&=r\theta \\\\r\theta&=5 \\\\ 7\theta &=5 \\\\ \theta&=\dfrac{5}{7} \text{ rad}\\\\ \angle AOB&=\dfrac{5}{7}\times \dfrac{180}{3.\,142} \\\\ &=40.92^\circ. \end{aligned}\)
Area of shaded region,
\(\begin{aligned} &=\dfrac{1}{2}r^2(\theta-\sin \theta) \\\\ &=\dfrac{1}{2}(7)^2 \begin{pmatrix} \dfrac{5}{7}-\sin40.92^\circ \end{pmatrix} \\\\ &=\dfrac{1}{2}(49)(0.\,0593) \\\\ &=1.\, 4529 \text{ cm}^2.\end{aligned}\)
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