Penyelesaian masalah

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Penyelesaian Masalah

2.4

Penyelesaian Masalah

CONTOH 1:

Ali berbelanja RM 230. Kakaknya pula berbelanja 250% daripada perbelanjaan Ali. Kira perbelanjaan kakaknya.

PENYELESAIAN:

Belanja Ali: RM 230
Belanja kakak Ali: RM 230 \(\times\) 250%

\(=\frac{25\cancel0}{1\cancel0\cancel0}\times\text{ RM }23\cancel0\)

\(=25 \times\text{RM }23\)

\(=\text{RM }575\)

Maka, belanja kakak Ali ialah RM 575.

CONTOH 2:

Tukar peratus kepada nombor bercampur dan perpuluhan.
a) 130%
b) 370%
c) 412%
d) 505%

PENYELESAIAN:

\(\text{a) }130\%\to\frac{130}{100}\\ \,\,\,\,\,\,\frac{13\cancel0}{10\cancel0}\to\frac{13}{10}\to1\frac{3}{10}\)

Dalam perpuluhan,

\(1\frac{3}{10}\to1.3\)

\(\text{b) }370\%\to\frac{370}{100}\\ \,\,\,\,\,\,\frac{37\cancel0}{10\cancel0}\to\frac{37}{10}\to3\frac{7}{10} \)

Dalam perpuluhan,

\(3\frac{7}{10}\to3.7\)

\(\text{c) }412\%\to\frac{412}{100}\to4\frac{12}{100}\\ \,\,\,\,\,\,4\frac{12\,\div\,4}{100\,\div\,4}=4\frac{3}{25}\\ \)

Dalam perpuluhan,

\(4\frac{12}{100}\to4.12\)

\(\text{d) }505\%\to\frac{505}{100}\to5\frac{5}{100}\\ \,\,\,\,\,\,\,5\frac{5\,\div\,5}{100\,\div\,5}=5\frac{1}{20}\)

Dalam perpuluhan

\(5\frac{5}{100}\to5.05\)