The following diagram shows that \(EFGH\) is a rectangle drawn on a Cartesian plane.

\(M\) is the midpoint of \(EH.\) 

State the coordinate of \(G\).

Given that midpoint \(EH\) is \(M(8,6)\).

\(\begin{aligned} (8,6)&= (\dfrac {2+x} {2} , \dfrac{6+y}{2}) \end{aligned}\)

So, \(H= (14,6)\).

Noted that, \(EH\) is parallel to \(FG\) and \(x\)-axis. 

So, the \(x\)-coordinate of \(G\) is \(14\), while the \(y\)-coordinate of \(G\) is \(3\).

Thus, \(G = (14, 3).\)